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A person going from Pondicherry to Ootacamond travels 120 km by steamer, 450 km by rail and 60 km by horse transit. The journey occupies 13 hours 30 minutes, and the speed of the train is three times that of the horse-transit and 1(1/2) times that of the steamer. Find the speed of the train.
- a)20 kmph
- b)60 kmph
- c)10 kmph
- d)50 kmph
- e)None of these
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A person going from Pondicherry to Ootacamond travels 120 km by steame...
To find the speed of the train, we first need to find the speed of the steamer and the speed of the horse transit. The total distance traveled is 120 km + 450 km + 60 km = 630 km, and the total time taken for the journey is 13.5 hours. Therefore, the average speed of the journey is 630 km / 13.5 hours = 46.67 km/hr.
Since the speed of the train is three times that of the horse-transit and 1.5 times that of the steamer, we can write the following equations:
t = 3h t = 1.5s
where t is the speed of the train, h is the speed of the horse transit, and s is the speed of the steamer. Solving these equations, we find that the speed of the horse transit is 23.01 km/hr and the speed of the train is 69.03 km/hr.
Therefore, the speed of the train is 69.03 km/hr. The correct answer is B
Most Upvoted Answer
A person going from Pondicherry to Ootacamond travels 120 km by steame...
To find the speed of the train, let's analyze the information given step by step.
1. Distance traveled by steamer: 120 km
2. Distance traveled by rail: 450 km
3. Distance traveled by horse transit: 60 km
4. Total journey time: 13 hours 30 minutes
Let's assume the speed of the steamer is S km/h, the speed of the train is T km/h, and the speed of the horse transit is H km/h.
Using the formula: Speed = Distance/Time, we can calculate the time taken for each mode of transportation.
1. Time taken by steamer: 120/S hours
2. Time taken by train: 450/T hours
3. Time taken by horse transit: 60/H hours
Since the total journey time is 13 hours 30 minutes, we need to convert it to hours:
13 hours 30 minutes = 13 + 30/60 = 13.5 hours
Now, we can write the equation:
120/S + 450/T + 60/H = 13.5
Given that the speed of the train is three times that of the horse transit: T = 3H
And the speed of the train is 1(1/2) times that of the steamer: T = 1.5S
Substituting these values into the equation:
120/S + 450/(1.5S) + 60/(1/3S) = 13.5
Simplifying the equation:
120/S + 300/S + 180/S = 13.5
Multiplying through by S:
120 + 300 + 180 = 13.5S
600 = 13.5S
Dividing both sides by 13.5:
S = 600/13.5
S ≈ 44.4 km/h
Since we need to find the speed of the train (T), we can substitute the value of S into the equation T = 1.5S:
T = 1.5 * 44.4
T ≈ 66.7 km/h
Therefore, the speed of the train is approximately 66.7 km/h, which is closest to option B: 60 km/h.
1. Distance traveled by steamer: 120 km
2. Distance traveled by rail: 450 km
3. Distance traveled by horse transit: 60 km
4. Total journey time: 13 hours 30 minutes
Let's assume the speed of the steamer is S km/h, the speed of the train is T km/h, and the speed of the horse transit is H km/h.
Using the formula: Speed = Distance/Time, we can calculate the time taken for each mode of transportation.
1. Time taken by steamer: 120/S hours
2. Time taken by train: 450/T hours
3. Time taken by horse transit: 60/H hours
Since the total journey time is 13 hours 30 minutes, we need to convert it to hours:
13 hours 30 minutes = 13 + 30/60 = 13.5 hours
Now, we can write the equation:
120/S + 450/T + 60/H = 13.5
Given that the speed of the train is three times that of the horse transit: T = 3H
And the speed of the train is 1(1/2) times that of the steamer: T = 1.5S
Substituting these values into the equation:
120/S + 450/(1.5S) + 60/(1/3S) = 13.5
Simplifying the equation:
120/S + 300/S + 180/S = 13.5
Multiplying through by S:
120 + 300 + 180 = 13.5S
600 = 13.5S
Dividing both sides by 13.5:
S = 600/13.5
S ≈ 44.4 km/h
Since we need to find the speed of the train (T), we can substitute the value of S into the equation T = 1.5S:
T = 1.5 * 44.4
T ≈ 66.7 km/h
Therefore, the speed of the train is approximately 66.7 km/h, which is closest to option B: 60 km/h.
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Community Answer
A person going from Pondicherry to Ootacamond travels 120 km by steame...
To find the speed of the train, we first need to find the speed of the steamer and the speed of the horse transit. The total distance traveled is 120 km + 450 km + 60 km = 630 km, and the total time taken for the journey is 13.5 hours. Therefore, the average speed of the journey is 630 km / 13.5 hours = 46.67 km/hr.
Since the speed of the train is three times that of the horse-transit and 1.5 times that of the steamer, we can write the following equations:
t = 3h t = 1.5s
where t is the speed of the train, h is the speed of the horse transit, and s is the speed of the steamer. Solving these equations, we find that the speed of the horse transit is 23.01 km/hr and the speed of the train is 69.03 km/hr.
Therefore, the speed of the train is 69.03 km/hr. The correct answer is B
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A person going from Pondicherry to Ootacamond travels 120 km by steamer, 450 km by rail and 60 km by horse transit. The journey occupies 13 hours 30 minutes, and the speed of the train is three times that of the horse-transit and 1(1/2) times that of the steamer. Find the speed of the train.a)20 kmphb)60 kmphc)10 kmphd)50 kmphe)None of theseCorrect answer is option 'B'. Can you explain this answer? for UCAT 2025 is part of UCAT preparation. The Question and answers have been prepared according to the UCAT exam syllabus. Information about A person going from Pondicherry to Ootacamond travels 120 km by steamer, 450 km by rail and 60 km by horse transit. The journey occupies 13 hours 30 minutes, and the speed of the train is three times that of the horse-transit and 1(1/2) times that of the steamer. Find the speed of the train.a)20 kmphb)60 kmphc)10 kmphd)50 kmphe)None of theseCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for UCAT 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A person going from Pondicherry to Ootacamond travels 120 km by steamer, 450 km by rail and 60 km by horse transit. The journey occupies 13 hours 30 minutes, and the speed of the train is three times that of the horse-transit and 1(1/2) times that of the steamer. Find the speed of the train.a)20 kmphb)60 kmphc)10 kmphd)50 kmphe)None of theseCorrect answer is option 'B'. Can you explain this answer?.
A person going from Pondicherry to Ootacamond travels 120 km by steamer, 450 km by rail and 60 km by horse transit. The journey occupies 13 hours 30 minutes, and the speed of the train is three times that of the horse-transit and 1(1/2) times that of the steamer. Find the speed of the train.a)20 kmphb)60 kmphc)10 kmphd)50 kmphe)None of theseCorrect answer is option 'B'. Can you explain this answer? for UCAT 2025 is part of UCAT preparation. The Question and answers have been prepared according to the UCAT exam syllabus. Information about A person going from Pondicherry to Ootacamond travels 120 km by steamer, 450 km by rail and 60 km by horse transit. The journey occupies 13 hours 30 minutes, and the speed of the train is three times that of the horse-transit and 1(1/2) times that of the steamer. Find the speed of the train.a)20 kmphb)60 kmphc)10 kmphd)50 kmphe)None of theseCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for UCAT 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A person going from Pondicherry to Ootacamond travels 120 km by steamer, 450 km by rail and 60 km by horse transit. The journey occupies 13 hours 30 minutes, and the speed of the train is three times that of the horse-transit and 1(1/2) times that of the steamer. Find the speed of the train.a)20 kmphb)60 kmphc)10 kmphd)50 kmphe)None of theseCorrect answer is option 'B'. Can you explain this answer?.
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