If the numerator of a fraction is increased by 140 % and the denominat...
Let the original fraction be x/y.
Then new fraction

Therefore 24/25(x/y) = 4/15
⇒ x/y = (4/15 Ã - 25/24) = 5/18
Therefore Original Fraction = 5/18
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If the numerator of a fraction is increased by 140 % and the denominat...
To solve this problem, let's assume the original fraction is a/b.
Given that the numerator is increased by 140%, we can write the new numerator as (a + 1.4a) = 2.4a.
Similarly, the denominator is increased by 150%, so the new denominator can be written as (b + 1.5b) = 2.5b.
We are given that the resultant fraction is 4/15. So we can set up the equation:
2.4a / 2.5b = 4/15
Let's cross multiply to solve for a and b:
(2.4a) * 15 = (2.5b) * 4
36a = 10b
Now, we need to find a and b in terms of each other. We can divide both sides of the equation by 2:
18a = 5b
Now we have two equations:
36a = 10b
18a = 5b
To find the value of a and b, let's divide the second equation by 18:
a = (5b)/18
Now, substitute this value of a in the first equation:
36((5b)/18) = 10b
Simplify the equation:
10b = 10b
This equation is true for any value of b. Therefore, b can be any value.
To find the original fraction, we can choose a specific value for b. Let's choose b = 1.
Using this value, we can find the value of a:
a = (5(1))/18
a = 5/18
Therefore, the original fraction is 5/18.
However, none of the answer choices given match this fraction. So, it seems there may be an error in the question or answer choices provided.
If the numerator of a fraction is increased by 140 % and the denominat...
Let the original fraction be x/y.
Then new fraction

Therefore 24/25(x/y) = 4/15
⇒ x/y = (4/15 Ã - 25/24) = 5/18
Therefore Original Fraction = 5/18