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In two successive years, 100 and 75 students of a school appeared at the final examination. Respectively 75 % and 60 % of them passed. The average rate of pass is:
- a)68 4/7 %
- b)78 %
- c)80 %
- d)80 4/7 %
- e)None of these
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
In two successive years, 100 and 75 students of a school appeared at t...
Total candidates = (100 + 75) = 175
Total passed = (75/100 Ã- 100) + (60/100 Ã- 75)
= (75 + 45) = 120
Therefore Pass % = (120/175 Ã -100)%
= 480/7 % = 68 4/7 %
Total passed = (75/100 Ã- 100) + (60/100 Ã- 75)
= (75 + 45) = 120
Therefore Pass % = (120/175 Ã -100)%
= 480/7 % = 68 4/7 %
Most Upvoted Answer
In two successive years, 100 and 75 students of a school appeared at t...
Given Information:
- In the first year, 100 students appeared at the final examination and 75% of them passed.
- In the second year, 75 students appeared at the final examination and 60% of them passed.
To Find:
The average rate of pass.
Solution:
To find the average rate of pass, we need to calculate the total number of students who passed in both years and divide it by the total number of students who appeared in both years.
Step 1: Calculate the number of students who passed in each year:
- In the first year, 75% of 100 students passed. So, the number of students who passed = (75/100) * 100 = 75.
- In the second year, 60% of 75 students passed. So, the number of students who passed = (60/100) * 75 = 45.
Step 2: Calculate the total number of students who appeared in both years:
- Total number of students who appeared = 100 + 75 = 175.
Step 3: Calculate the total number of students who passed in both years:
- Number of students who passed in both years = 75 + 45 = 120.
Step 4: Calculate the average rate of pass:
- Average rate of pass = (Number of students who passed in both years / Total number of students who appeared) * 100.
- Average rate of pass = (120/175) * 100 = 68.57%.
So, the average rate of pass is approximately 68.57%, which can be rounded off to 68 4/7%.
Therefore, the correct answer is option 'A' (68 4/7%).
- In the first year, 100 students appeared at the final examination and 75% of them passed.
- In the second year, 75 students appeared at the final examination and 60% of them passed.
To Find:
The average rate of pass.
Solution:
To find the average rate of pass, we need to calculate the total number of students who passed in both years and divide it by the total number of students who appeared in both years.
Step 1: Calculate the number of students who passed in each year:
- In the first year, 75% of 100 students passed. So, the number of students who passed = (75/100) * 100 = 75.
- In the second year, 60% of 75 students passed. So, the number of students who passed = (60/100) * 75 = 45.
Step 2: Calculate the total number of students who appeared in both years:
- Total number of students who appeared = 100 + 75 = 175.
Step 3: Calculate the total number of students who passed in both years:
- Number of students who passed in both years = 75 + 45 = 120.
Step 4: Calculate the average rate of pass:
- Average rate of pass = (Number of students who passed in both years / Total number of students who appeared) * 100.
- Average rate of pass = (120/175) * 100 = 68.57%.
So, the average rate of pass is approximately 68.57%, which can be rounded off to 68 4/7%.
Therefore, the correct answer is option 'A' (68 4/7%).
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Community Answer
In two successive years, 100 and 75 students of a school appeared at t...
Total candidates = (100 + 75) = 175
Total passed = (75/100 Ã- 100) + (60/100 Ã- 75)
= (75 + 45) = 120
Therefore Pass % = (120/175 Ã -100)%
= 480/7 % = 68 4/7 %
Total passed = (75/100 Ã- 100) + (60/100 Ã- 75)
= (75 + 45) = 120
Therefore Pass % = (120/175 Ã -100)%
= 480/7 % = 68 4/7 %
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