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Uranium hexafluoride can leech into the air by bonding to water vapor to form UO2F2 and HF, both of which are toxic to humans. Which of the following describes this reaction?
- a)UF6 + 4H2O → UO2F2 + HF
- b)UF6 + 2H2O → UO2 F2 + 4HF
- c)UF6 + 2H2O → 3UO2 F2 + HF
- d)UF6 + H2O → UO2 F2 + 2HF
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
Uranium hexafluoride can leech into the air by bonding to water vapor ...
- Start by balancing the U, which only appears once on each side of the reaction
- Next balance oxygen and hydrogen, which both appears in one molecule on each side of the reaction
- Finally balance F, which appears multiple times on the right hand portion of the reaction
- The balanced reaction is UF6 + 2H2O → UO2 F2 + 4HF
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Community Answer
Uranium hexafluoride can leech into the air by bonding to water vapor ...
Understanding the Reaction
The reaction of uranium hexafluoride (UF6) with water (H2O) leads to the formation of uranium dioxide difluoride (UO2F2) and hydrogen fluoride (HF). The correct equation needs to balance the number of atoms on both sides.
Analyzing the Options
- Option a: UF6 + 4H2O → UO2F2 + HF
This option is incorrect because it does not balance the fluorine atoms; there are too many water molecules and not enough HF produced.
- Option b: UF6 + 2H2O → UO2F2 + 4HF
This option is correct. It properly balances the fluorine and hydrogen atoms. One molecule of UF6 reacts with two molecules of water to yield one molecule of UO2F2 and four molecules of HF.
- Option c: UF6 + 2H2O → 3UO2F2 + HF
This option is incorrect as it produces too much UO2F2 and does not balance the fluorine atoms.
- Option d: UF6 + H2O → UO2F2 + 2HF
This option is also incorrect. It does not provide the correct stoichiometry for the reaction.
Conclusion
The correct answer is Option b because it accurately represents the stoichiometry of the reaction, ensuring that all atoms are accounted for on both sides of the equation. Understanding these reactions is crucial, especially given the toxic nature of the products involved.
The reaction of uranium hexafluoride (UF6) with water (H2O) leads to the formation of uranium dioxide difluoride (UO2F2) and hydrogen fluoride (HF). The correct equation needs to balance the number of atoms on both sides.
Analyzing the Options
- Option a: UF6 + 4H2O → UO2F2 + HF
This option is incorrect because it does not balance the fluorine atoms; there are too many water molecules and not enough HF produced.
- Option b: UF6 + 2H2O → UO2F2 + 4HF
This option is correct. It properly balances the fluorine and hydrogen atoms. One molecule of UF6 reacts with two molecules of water to yield one molecule of UO2F2 and four molecules of HF.
- Option c: UF6 + 2H2O → 3UO2F2 + HF
This option is incorrect as it produces too much UO2F2 and does not balance the fluorine atoms.
- Option d: UF6 + H2O → UO2F2 + 2HF
This option is also incorrect. It does not provide the correct stoichiometry for the reaction.
Conclusion
The correct answer is Option b because it accurately represents the stoichiometry of the reaction, ensuring that all atoms are accounted for on both sides of the equation. Understanding these reactions is crucial, especially given the toxic nature of the products involved.
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Uranium hexafluoride can leech into the air by bonding to water vapor to form UO2F2 and HF,both of which are toxic to humans. Which of the following describes this reaction?a)UF6+ 4H2O → UO2F2+ HFb)UF6+ 2H2O → UO2F2+ 4HFc)UF6+ 2H2O → 3UO2F2+ HFd)UF6+ H2O → UO2F2+ 2HFCorrect answer is option 'B'. Can you explain this answer? for MCAT 2025 is part of MCAT preparation. The Question and answers have been prepared according to the MCAT exam syllabus. Information about Uranium hexafluoride can leech into the air by bonding to water vapor to form UO2F2 and HF,both of which are toxic to humans. Which of the following describes this reaction?a)UF6+ 4H2O → UO2F2+ HFb)UF6+ 2H2O → UO2F2+ 4HFc)UF6+ 2H2O → 3UO2F2+ HFd)UF6+ H2O → UO2F2+ 2HFCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for MCAT 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Uranium hexafluoride can leech into the air by bonding to water vapor to form UO2F2 and HF,both of which are toxic to humans. Which of the following describes this reaction?a)UF6+ 4H2O → UO2F2+ HFb)UF6+ 2H2O → UO2F2+ 4HFc)UF6+ 2H2O → 3UO2F2+ HFd)UF6+ H2O → UO2F2+ 2HFCorrect answer is option 'B'. Can you explain this answer?.
Uranium hexafluoride can leech into the air by bonding to water vapor to form UO2F2 and HF,both of which are toxic to humans. Which of the following describes this reaction?a)UF6+ 4H2O → UO2F2+ HFb)UF6+ 2H2O → UO2F2+ 4HFc)UF6+ 2H2O → 3UO2F2+ HFd)UF6+ H2O → UO2F2+ 2HFCorrect answer is option 'B'. Can you explain this answer? for MCAT 2025 is part of MCAT preparation. The Question and answers have been prepared according to the MCAT exam syllabus. Information about Uranium hexafluoride can leech into the air by bonding to water vapor to form UO2F2 and HF,both of which are toxic to humans. Which of the following describes this reaction?a)UF6+ 4H2O → UO2F2+ HFb)UF6+ 2H2O → UO2F2+ 4HFc)UF6+ 2H2O → 3UO2F2+ HFd)UF6+ H2O → UO2F2+ 2HFCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for MCAT 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Uranium hexafluoride can leech into the air by bonding to water vapor to form UO2F2 and HF,both of which are toxic to humans. Which of the following describes this reaction?a)UF6+ 4H2O → UO2F2+ HFb)UF6+ 2H2O → UO2F2+ 4HFc)UF6+ 2H2O → 3UO2F2+ HFd)UF6+ H2O → UO2F2+ 2HFCorrect answer is option 'B'. Can you explain this answer?.
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