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Triangle ABC is right angled at c and CD is perpendicular to AB,Angle A =55degree.find angle ACD 2)angle BCD and angleABC?
Verified Answer
Triangle ABC is right angled at c and CD is perpendicular to AB,Angle ...
Ans.

Method to Solve :

In the triangle ABC , 3. Angle BDC = 90� .given

Therefore Angle CBD +BDC +BCD= 180.Sum of angles of triangle

40�+90�+BCD=180�

130�+BCD=180�

BCD=50�


 Angle ACB=90  .given

Angle ACB=Angle ACD+BCD

90�=ACD+50�

Angle ACD=40�


 Angle ABC=40�  .(A-D-B)

ACB+ABC+BAC=180� .Sum of angles of triangle

Therefore 90�+40�+BAC=180�

130�+BAC=180�

BAC=50�

This question is part of UPSC exam. View all Class 7 courses
Most Upvoted Answer
Triangle ABC is right angled at c and CD is perpendicular to AB,Angle ...
Angle ACD:
- In triangle ABC, angle A is given as 55 degrees and angle C is a right angle.
- Since the sum of angles in a triangle is 180 degrees, we can find angle B by subtracting angles A and C from 180 degrees.
- Angle B = 180 degrees - 55 degrees - 90 degrees (angle C) = 35 degrees.
- CD is perpendicular to AB, so angle ACD is a right angle.
- Therefore, angle ACD = 90 degrees.

Angle BCD:
- In triangle BCD, angle BCD is a right angle because CD is perpendicular to AB.
- We know that angle ACD is 90 degrees (as calculated above).
- The sum of angles in triangle BCD is 180 degrees, so we can find angle BCD by subtracting angles ACD and B from 180 degrees.
- Angle BCD = 180 degrees - 90 degrees - 90 degrees (angle B) = 0 degrees.
- Therefore, angle BCD is 0 degrees.

Angle ABC:
- In triangle ABC, angle ABC is the right angle at C.
- The sum of angles in a triangle is 180 degrees, so we can find angle ABC by subtracting angles A and C from 180 degrees.
- Angle ABC = 180 degrees - 55 degrees - 90 degrees (angle C) = 35 degrees.
Community Answer
Triangle ABC is right angled at c and CD is perpendicular to AB,Angle ...
AREA OF TRIANGLE ABC=30CM AND LENGHT OF AD=60UPON13CM
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