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An electromagnetic wave of frequency f = 7.3MHz passes from a vacuum into a dielectric medium with permittivityε = 9. Then,
  • a)
    Frequency of the wave will remains same but wavelength will become thrice
  • b)
    Frequency remains same but the Velocity and wavelength both will become 3 times of the original value
  • c)
    Velocity and frequency both will become 1/3 times of the original value
  • d)
    Frequency remains same but the Velocity and wavelength both will become 1/3 times of the original value
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
An electromagnetic wave of frequency f = 7.3MHz passes from a vacuum i...
As permittivity is greater than the permittivity of free space so the refractive index of medium is

Wavelength of the electromagnetic wave in medium will be 
Velocity of wave will be. 
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Community Answer
An electromagnetic wave of frequency f = 7.3MHz passes from a vacuum i...
To find the speed of an electromagnetic wave in a dielectric medium, we can use the equation:

v = c / √(ε)

Where:
v = speed of light in the dielectric medium
c = speed of light in a vacuum (approximately 3 x 10^8 m/s)
ε = permittivity of the dielectric medium

Given the frequency of the wave in the vacuum (f = 7.3 MHz), we can find the wavelength (λ) using the equation:

λ = c / f

Substituting this value into the equation for v, we have:

v = c / √(ε)

Let's assume the permittivity of the dielectric medium is ε = ε₀ * εᵣ, where ε₀ is the permittivity of a vacuum (approximately 8.854 x 10^-12 F/m) and εᵣ is the relative permittivity of the dielectric medium.

Therefore, we can rewrite the equation as:

v = c / √(ε₀ * εᵣ)

Now, we can substitute the given frequency of 7.3 MHz into the equation for λ:

λ = c / f
λ = (3 x 10^8 m/s) / (7.3 x 10^6 Hz)
λ = 41.1 m

Substituting the values for λ and ε into the equation for v:

v = (3 x 10^8 m/s) / √(ε₀ * εᵣ)

Note that ε₀ is a constant.

Therefore, the speed of the electromagnetic wave in the dielectric medium is:

v = (3 x 10^8 m/s) / √(ε₀ * εᵣ)
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An electromagnetic wave of frequency f = 7.3MHz passes from a vacuum into a dielectric medium with permittivityε = 9. Then,a)Frequency of the wave will remains same but wavelength will become thriceb)Frequency remains same but the Velocity and wavelength both will become 3 times of the original valuec)Velocity and frequency both will become 1/3times of the original valued)Frequency remains same but the Velocity and wavelength both will become 1/3 times of the original valueCorrect answer is option 'D'. Can you explain this answer?
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An electromagnetic wave of frequency f = 7.3MHz passes from a vacuum into a dielectric medium with permittivityε = 9. Then,a)Frequency of the wave will remains same but wavelength will become thriceb)Frequency remains same but the Velocity and wavelength both will become 3 times of the original valuec)Velocity and frequency both will become 1/3times of the original valued)Frequency remains same but the Velocity and wavelength both will become 1/3 times of the original valueCorrect answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about An electromagnetic wave of frequency f = 7.3MHz passes from a vacuum into a dielectric medium with permittivityε = 9. Then,a)Frequency of the wave will remains same but wavelength will become thriceb)Frequency remains same but the Velocity and wavelength both will become 3 times of the original valuec)Velocity and frequency both will become 1/3times of the original valued)Frequency remains same but the Velocity and wavelength both will become 1/3 times of the original valueCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An electromagnetic wave of frequency f = 7.3MHz passes from a vacuum into a dielectric medium with permittivityε = 9. Then,a)Frequency of the wave will remains same but wavelength will become thriceb)Frequency remains same but the Velocity and wavelength both will become 3 times of the original valuec)Velocity and frequency both will become 1/3times of the original valued)Frequency remains same but the Velocity and wavelength both will become 1/3 times of the original valueCorrect answer is option 'D'. Can you explain this answer?.
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