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When an object is placed 45 centimeters in front of a diverging lens with a focal length of 15 centimeters, what are the image distance and the magnification?
  • a)
    d = 22.25 cm and m = -1.0
  • b)
    d = -11.25 cm and m = 0.25
  • c)
    d = -22.25 cm and m = 0.25
  • d)
    d = 10.25 cm and m = 4.1
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
When an object is placed 45 centimeters in front of a diverging lens w...
  • This is a straightforward application of the thin lens formula although you could get a rough estimate from drawing a ray diagram:
  • The values from the question stem are f = -15 cm and o = 45 cm. The focal length for diverging lens are negative. Object length is positive moving left starting from the lens.
  • Plug in your values:
  • Magnification is calculated from the image and object distances:
  • The image is 11.25 cm to the left of the lens with a reduced size of 0.25.
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Community Answer
When an object is placed 45 centimeters in front of a diverging lens w...
When an object is placed in front of a diverging lens, the lens will create a virtual image that is upright and reduced in size. To determine the image distance and magnification, we can use the lens formula and magnification formula.

The lens formula is given by:
1/f = 1/di - 1/do

Where:
f is the focal length of the lens
di is the image distance
do is the object distance

Given:
f = 15 cm
do = -45 cm (since the object is placed in front of the lens)

We can rearrange the lens formula to solve for di:
1/di = 1/f - 1/do

Substituting the given values:
1/di = 1/15 - 1/(-45)

Simplifying the equation:
1/di = (3 - 1)/45
1/di = 2/45

Taking the reciprocal of both sides:
di = 45/2
di = 22.5 cm

The image distance is 22.5 cm.

The magnification formula is given by:
m = -di/do

Substituting the given values:
m = -22.5/(-45)
m = 0.5

The magnification is 0.5.

Therefore, the correct answer is option B: d = -11.25 cm and m = 0.25.
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When an object is placed 45 centimeters in front of a diverging lens with a focal length of 15 centimeters, what are the image distance and the magnification?a)d = 22.25 cm and m = -1.0b)d = -11.25 cm and m = 0.25c)d = -22.25 cm and m = 0.25d)d = 10.25 cm and m = 4.1Correct answer is option 'B'. Can you explain this answer? for MCAT 2025 is part of MCAT preparation. The Question and answers have been prepared according to the MCAT exam syllabus. Information about When an object is placed 45 centimeters in front of a diverging lens with a focal length of 15 centimeters, what are the image distance and the magnification?a)d = 22.25 cm and m = -1.0b)d = -11.25 cm and m = 0.25c)d = -22.25 cm and m = 0.25d)d = 10.25 cm and m = 4.1Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for MCAT 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for When an object is placed 45 centimeters in front of a diverging lens with a focal length of 15 centimeters, what are the image distance and the magnification?a)d = 22.25 cm and m = -1.0b)d = -11.25 cm and m = 0.25c)d = -22.25 cm and m = 0.25d)d = 10.25 cm and m = 4.1Correct answer is option 'B'. Can you explain this answer?.
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