MCAT Exam > MCAT Questions > The magnitude of electric field experienced b...
Start Learning for Free
The magnitude of electric field experienced by a charge at a certain distance from a source charge is equal to 64 N/C. What will be the magnitude of the electric field at four times that distance and with a source charge half as strong?
- a)1 N/C
- b)2 N/C
- c)64 N/C
- d)128 N/C
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
The magnitude of electric field experienced by a charge at a certain d...
- The equation for determining the electric field is
Where r is the distance between the charges, Q is the source charge, and k0 is Coulomb's constant. - If we use the equation for determining the electric field and change the value of r to 4r and change the value of
we obtain:
- Simplifying our formula, we obtain:
Indicating that the adjusted electric field will be 1/32 the magnitude of the original electric field. - The original electric field was 64 N/C, which means that the new adjusted electric field will be 64/32 = 2N/C.
Free Test
FREE
| Start Free Test |
Community Answer
The magnitude of electric field experienced by a charge at a certain d...
The magnitude of the electric field is given by Coulomb's Law, which states that the electric field (E) is directly proportional to the source charge (Q) and inversely proportional to the square of the distance (r) between the source charge and the point where the electric field is being measured. Mathematically, this can be expressed as:
E = k * (Q/r^2)
where k is the electrostatic constant.
In this question, we are given that the magnitude of the electric field at a certain distance (let's call it r1) is 64 N/C. Let's assume that the source charge at this distance is Q1.
So, we have:
64 = k * (Q1/r1^2) ...(1)
Now, we need to find the magnitude of the electric field at four times the distance (4r1) with a source charge half as strong (Q2 = Q1/2).
Using the same formula, we can write:
E' = k * (Q2/(4r1)^2) ...(2)
To find the magnitude of the electric field at 4r1, we can substitute 4r1 for r in equation (1):
64 = k * (Q1/(4r1)^2)
Simplifying this equation, we get:
64 = k * (Q1/16r1^2)
Multiplying both sides of the equation by 16, we get:
1024 = k * (Q1/r1^2)
This equation is equivalent to equation (1), which means that the magnitude of the electric field at 4r1 is also 64 N/C.
Now, let's substitute the values into equation (2) to find the magnitude of the electric field at 4r1 with a source charge half as strong:
E' = k * (Q2/(4r1)^2)
E' = k * ((Q1/2)/(4r1)^2)
E' = k * (Q1/8r1^2)
Since we know that the magnitude of the electric field at 4r1 is 64 N/C, we can write:
64 = k * (Q1/8r1^2)
Simplifying this equation, we get:
512 = k * (Q1/r1^2)
Comparing this equation with equation (1), we can see that the magnitude of the electric field at 4r1 with a source charge half as strong is 512 N/C.
Therefore, the correct answer is option B) 2 N/C.
E = k * (Q/r^2)
where k is the electrostatic constant.
In this question, we are given that the magnitude of the electric field at a certain distance (let's call it r1) is 64 N/C. Let's assume that the source charge at this distance is Q1.
So, we have:
64 = k * (Q1/r1^2) ...(1)
Now, we need to find the magnitude of the electric field at four times the distance (4r1) with a source charge half as strong (Q2 = Q1/2).
Using the same formula, we can write:
E' = k * (Q2/(4r1)^2) ...(2)
To find the magnitude of the electric field at 4r1, we can substitute 4r1 for r in equation (1):
64 = k * (Q1/(4r1)^2)
Simplifying this equation, we get:
64 = k * (Q1/16r1^2)
Multiplying both sides of the equation by 16, we get:
1024 = k * (Q1/r1^2)
This equation is equivalent to equation (1), which means that the magnitude of the electric field at 4r1 is also 64 N/C.
Now, let's substitute the values into equation (2) to find the magnitude of the electric field at 4r1 with a source charge half as strong:
E' = k * (Q2/(4r1)^2)
E' = k * ((Q1/2)/(4r1)^2)
E' = k * (Q1/8r1^2)
Since we know that the magnitude of the electric field at 4r1 is 64 N/C, we can write:
64 = k * (Q1/8r1^2)
Simplifying this equation, we get:
512 = k * (Q1/r1^2)
Comparing this equation with equation (1), we can see that the magnitude of the electric field at 4r1 with a source charge half as strong is 512 N/C.
Therefore, the correct answer is option B) 2 N/C.
|
Explore Courses for MCAT exam
|
|
Top Courses for MCATView all
Question Description
The magnitude of electric field experienced by a charge at a certain distance from a source charge is equal to64 N/C. What will be the magnitude of the electric field at four times that distance and with a source charge half as strong?a)1 N/Cb)2 N/Cc)64 N/Cd)128 N/CCorrect answer is option 'B'. Can you explain this answer? for MCAT 2025 is part of MCAT preparation. The Question and answers have been prepared according to the MCAT exam syllabus. Information about The magnitude of electric field experienced by a charge at a certain distance from a source charge is equal to64 N/C. What will be the magnitude of the electric field at four times that distance and with a source charge half as strong?a)1 N/Cb)2 N/Cc)64 N/Cd)128 N/CCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for MCAT 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The magnitude of electric field experienced by a charge at a certain distance from a source charge is equal to64 N/C. What will be the magnitude of the electric field at four times that distance and with a source charge half as strong?a)1 N/Cb)2 N/Cc)64 N/Cd)128 N/CCorrect answer is option 'B'. Can you explain this answer?.
The magnitude of electric field experienced by a charge at a certain distance from a source charge is equal to64 N/C. What will be the magnitude of the electric field at four times that distance and with a source charge half as strong?a)1 N/Cb)2 N/Cc)64 N/Cd)128 N/CCorrect answer is option 'B'. Can you explain this answer? for MCAT 2025 is part of MCAT preparation. The Question and answers have been prepared according to the MCAT exam syllabus. Information about The magnitude of electric field experienced by a charge at a certain distance from a source charge is equal to64 N/C. What will be the magnitude of the electric field at four times that distance and with a source charge half as strong?a)1 N/Cb)2 N/Cc)64 N/Cd)128 N/CCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for MCAT 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The magnitude of electric field experienced by a charge at a certain distance from a source charge is equal to64 N/C. What will be the magnitude of the electric field at four times that distance and with a source charge half as strong?a)1 N/Cb)2 N/Cc)64 N/Cd)128 N/CCorrect answer is option 'B'. Can you explain this answer?.
Solutions for The magnitude of electric field experienced by a charge at a certain distance from a source charge is equal to64 N/C. What will be the magnitude of the electric field at four times that distance and with a source charge half as strong?a)1 N/Cb)2 N/Cc)64 N/Cd)128 N/CCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for MCAT.
Download more important topics, notes, lectures and mock test series for MCAT Exam by signing up for free.
Here you can find the meaning of The magnitude of electric field experienced by a charge at a certain distance from a source charge is equal to64 N/C. What will be the magnitude of the electric field at four times that distance and with a source charge half as strong?a)1 N/Cb)2 N/Cc)64 N/Cd)128 N/CCorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
The magnitude of electric field experienced by a charge at a certain distance from a source charge is equal to64 N/C. What will be the magnitude of the electric field at four times that distance and with a source charge half as strong?a)1 N/Cb)2 N/Cc)64 N/Cd)128 N/CCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for The magnitude of electric field experienced by a charge at a certain distance from a source charge is equal to64 N/C. What will be the magnitude of the electric field at four times that distance and with a source charge half as strong?a)1 N/Cb)2 N/Cc)64 N/Cd)128 N/CCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of The magnitude of electric field experienced by a charge at a certain distance from a source charge is equal to64 N/C. What will be the magnitude of the electric field at four times that distance and with a source charge half as strong?a)1 N/Cb)2 N/Cc)64 N/Cd)128 N/CCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice The magnitude of electric field experienced by a charge at a certain distance from a source charge is equal to64 N/C. What will be the magnitude of the electric field at four times that distance and with a source charge half as strong?a)1 N/Cb)2 N/Cc)64 N/Cd)128 N/CCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice MCAT tests.
|
|
Explore Courses for MCAT exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup