A potential barrier of 0.5V exist across a PN junction. If the depletion region is 5 * 10-7 m wide the intensity of the electric field in this region is :?

Question

Answer

As we know that V=E*d therefore 0.5/5*10-7=E therfore ans is 10power6

Answer

10*6

Answer

Calculating the electric field intensity in the depletion region:

The potential barrier across a PN junction is given as 0.5V and the width of the depletion region is 5 * 10^-7 m.

Formula:
The electric field intensity (E) in the depletion region can be calculated using the formula:
E = V / d

Where:
E = Electric field intensity
V = Potential barrier
d = Width of the depletion region

Calculation:
Given V = 0.5V and d = 5 * 10^-7 m

Substitute the values into the formula:
E = 0.5 / 5 * 10^-7
E = 0.5 / 0.0000005
E = 1000000 V/m

Therefore, the intensity of the electric field in the depletion region is 1000000 V/m. This means that the electric field in the depletion region is quite strong due to the narrow width of the region and the relatively high potential barrier across the PN junction.

Answer

How...plz explain me in detail

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