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The cause of the potential barrier in a p-n diodeis [1998]
  • a)
    depletion of positive charges near thejunction
  • b)
    concentration of positive charges near thejunction
  • c)
    depletion of negative charges near thejunction
  • d)
    concentration of positive and negativecharges near the junction
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
The cause of the potential barrier in a p-n diodeis [1998]a)depletion ...
During the formation of a junction diode,
holes from p-region diffuse into n-region and
electrons from n-region diffuse into p-region.
In both cases, when an electron meets a hole,
they cancel the effect of each other and as a
result, a thin layer at the junction becomes
free from any of charge carriers. This is called
depletion layer. There is a potential gradient
in the depletion layer, negative on the p-side
and positive on the n-side. The potential
difference thus developed across the
junction is called potential barrier.
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Most Upvoted Answer
The cause of the potential barrier in a p-n diodeis [1998]a)depletion ...
The correct option is (d) concentration of positive and negative charges near the junction.
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Community Answer
The cause of the potential barrier in a p-n diodeis [1998]a)depletion ...
Understanding the Potential Barrier in a P-N Diode
The potential barrier in a p-n diode is a crucial concept in semiconductor physics. It arises due to the interaction between p-type and n-type materials.
Formation of the Depletion Region
- When p-type and n-type materials are joined, electrons from the n-side (which has excess negative charge carriers) diffuse into the p-side.
- Simultaneously, holes from the p-side (which has excess positive charge carriers) diffuse into the n-side.
Charge Carrier Redistribution
- This diffusion of electrons and holes leads to the recombination of charge carriers at the junction.
- As electrons leave the n-side, it becomes positively charged, while the p-side loses positive charge carriers (holes), becoming negatively charged.
Creating the Electric Field
- The region around the junction becomes depleted of mobile charge carriers, forming the depletion region.
- The opposite charges (positive on the n-side and negative on the p-side) create an electric field.
Establishment of the Potential Barrier
- This electric field opposes further diffusion of electrons and holes, establishing a potential barrier.
- The potential barrier height is influenced by the concentration of these charge carriers, which is why the correct answer is option 'D': concentration of positive and negative charges near the junction.
Conclusion
In summary, the potential barrier in a p-n diode is created through the concentration of positive charges (holes) from the p-side and negative charges (electrons) from the n-side, leading to a depletion region and an electric field that prevents further charge carrier movement.
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Read the passage given below and answer the following questions:The rate of a reaction, which may also be called its velocity or speed, can be defined with relation to the concentration of any of the reacting substances, or to that of any product of the reaction. If the species chosen is a reactant which has a concentration c at time t the rate is - dc/dt, while the rate with reference to a product having a concentration x at time t is dx/dt. Any concentration units may be used for expressing the rate; thus, if moles per liter are employed for concentration and seconds for the time, the units for the rate are moles litre–1sec–1. For gas reactions pressure units are sometimes used in place of concentrations, so that legitimate units for the rate would be (mm. Hg) sec–1 and atm. sec–1 The order of a reaction concerns the dependence of the rate upon the concentrations of reacting substances; thus, if the rate is found experimentally to be proportional to the ath power of the concentration of one of the reactants A, to the both power of the concentration of a second reactant B, and so forth, via., rate = k CAα CAβ the over-all order of the reaction is simply n = α + β + ----- (2) Such a reaction is said to be of the αth order with respect to the substance A, the βth order with respect to B.In the following questions, a statement of Assertion followed by a statement of Reason is given. Choose the correct answer out of the following choices on the basis of the above passage.Assertion: For a reaction: P + 2Q → Products, Rate = k [P]1/2[Q]1 so the order of reaction is 1.5Reason: Order of reaction is the sum of stoichiometric coefficients of the reactants.

The cause of the potential barrier in a p-n diodeis [1998]a)depletion of positive charges near thejunctionb)concentration of positive charges near thejunctionc)depletion of negative charges near thejunctiond)concentration of positive and negativecharges near the junctionCorrect answer is option 'D'. Can you explain this answer?
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The cause of the potential barrier in a p-n diodeis [1998]a)depletion of positive charges near thejunctionb)concentration of positive charges near thejunctionc)depletion of negative charges near thejunctiond)concentration of positive and negativecharges near the junctionCorrect answer is option 'D'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about The cause of the potential barrier in a p-n diodeis [1998]a)depletion of positive charges near thejunctionb)concentration of positive charges near thejunctionc)depletion of negative charges near thejunctiond)concentration of positive and negativecharges near the junctionCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The cause of the potential barrier in a p-n diodeis [1998]a)depletion of positive charges near thejunctionb)concentration of positive charges near thejunctionc)depletion of negative charges near thejunctiond)concentration of positive and negativecharges near the junctionCorrect answer is option 'D'. Can you explain this answer?.
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