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For N204 gives 2N02 Kc is 1.14 calculate the free energy change for the reaction when concentration of two gases are 0.5 mol/litre each at same temperature?
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Read the passage given below and answer the following questions:The rate of a reaction, which may also be called its velocity or speed, can be defined with relation to the concentration of any of the reacting substances, or to that of any product of the reaction. If the species chosen is a reactant which has a concentration c at time t the rate is - dc/dt, while the rate with reference to a product having a concentration x at time t is dx/dt. Any concentration units may be used for expressing the rate; thus, if moles per liter are employed for concentration and seconds for the time, the units for the rate are moles litre–1sec–1. For gas reactions pressure units are sometimes used in place of concentrations, so that legitimate units for the rate would be (mm. Hg) sec–1 and atm. sec–1 The order of a reaction concerns the dependence of the rate upon the concentrations of reacting substances; thus, if the rate is found experimentally to be proportional to the ath power of the concentration of one of the reactants A, to the both power of the concentration of a second reactant B, and so forth, via., rate = k CAα CAβ the over-all order of the reaction is simply n = α + β + ----- (2) Such a reaction is said to be of the αth order with respect to the substance A, the βth order with respect to B.In the following questions, a statement of Assertion followed by a statement of Reason is given. Choose the correct answer out of the following choices on the basis of the above passage.Assertion: For a reaction: P + 2Q → Products, Rate = k [P]1/2[Q]1 so the order of reaction is 1.5Reason: Order of reaction is the sum of stoichiometric coefficients of the reactants.

For N204 gives 2N02 Kc is 1.14 calculate the free energy change for the reaction when concentration of two gases are 0.5 mol/litre each at same temperature?
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For N204 gives 2N02 Kc is 1.14 calculate the free energy change for the reaction when concentration of two gases are 0.5 mol/litre each at same temperature? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about For N204 gives 2N02 Kc is 1.14 calculate the free energy change for the reaction when concentration of two gases are 0.5 mol/litre each at same temperature? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For N204 gives 2N02 Kc is 1.14 calculate the free energy change for the reaction when concentration of two gases are 0.5 mol/litre each at same temperature?.
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