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The line which passes through the point (0 , 1) and perpendicular to the line x – 2y + 11 = 0 is
- a)2x + y – 1 = 0
- b)2x – y + 1 = 0
- c)2x – y + 3 = 0
- d)none of these
Correct answer is option 'A'. Can you explain this answer?
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The line which passes through the point (0 , 1) and perpendicular to t...
To find the equation of the line that passes through the point (0, 1) and is perpendicular to the line x = 2, we need to find the slope of the perpendicular line.
The line x = 2 is a vertical line with undefined slope. Any line perpendicular to a vertical line will have a slope of 0.
Therefore, the line passing through (0, 1) and perpendicular to x = 2 will have a slope of 0.
Using the point-slope form of a linear equation, which is y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope, we can write the equation of the line as:
y - 1 = 0(x - 0)
Simplifying this equation, we get:
y - 1 = 0
Therefore, the equation of the line passing through (0, 1) and perpendicular to x = 2 is y = 1.
The line x = 2 is a vertical line with undefined slope. Any line perpendicular to a vertical line will have a slope of 0.
Therefore, the line passing through (0, 1) and perpendicular to x = 2 will have a slope of 0.
Using the point-slope form of a linear equation, which is y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope, we can write the equation of the line as:
y - 1 = 0(x - 0)
Simplifying this equation, we get:
y - 1 = 0
Therefore, the equation of the line passing through (0, 1) and perpendicular to x = 2 is y = 1.
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The line which passes through the point (0 , 1) and perpendicular to the line x – 2y + 11 = 0 isa)2x + y – 1 = 0b)2x – y + 1 = 0c)2x – y + 3 = 0d)none of theseCorrect answer is option 'A'. Can you explain this answer?
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