A Ferrari Enzo is able to reach a speed of 134 miles per hour (60 mete...
To find displacement with constant acceleration, we can use the formula: d = Δt (va)
Our Δt should simply be 11 secs
Our va is simply the average velocity, which we can calculate using: va = 1/2(vf + vi) or va = ½ (0+60) which gives us va = 30 m/s
Using our initial formula, d = Δt (va), d = 11 sec x 30 m/s or d = 330 m
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A Ferrari Enzo is able to reach a speed of 134 miles per hour (60 mete...
To calculate the distance traveled by the Ferrari Enzo, we can use the kinematic equation:
\[d = v_i \cdot t + \frac{1}{2} \cdot a \cdot t^2\]
Where:
- \(d\) is the distance traveled
- \(v_i\) is the initial velocity
- \(t\) is the time taken
- \(a\) is the acceleration
Given:
- \(v_i = 0\) mph (initial velocity)
- \(t = 11\) seconds (time taken)
- \(a\) is unknown
To find \(a\), we can use the equation:
\[v_f = v_i + a \cdot t\]
Where:
- \(v_f\) is the final velocity
Given:
- \(v_f = 134\) mph (final velocity)
- \(v_i = 0\) mph (initial velocity)
- \(t = 11\) seconds (time taken)
Solving for \(a\):
\[a = \frac{v_f - v_i}{t}\]
Substituting the given values:
\[a = \frac{134 \, \text{mph} - 0 \, \text{mph}}{11 \, \text{s}}\]
\[a = \frac{134 \, \text{mph}}{11 \, \text{s}}\]
Converting mph to meters per second (m/s):
\[a = \frac{134 \, \text{mph} \cdot 0.44704 \, \text{m/s}}{11 \, \text{s}}\]
\[a \approx 5.45 \, \text{m/s}^2\]
Now that we have the value of \(a\), we can substitute it back into the distance formula:
\[d = 0 \cdot 11 + \frac{1}{2} \cdot 5.45 \cdot 11^2\]
\[d = \frac{1}{2} \cdot 5.45 \cdot 121\]
\[d \approx 330 \, \text{meters}\]
Therefore, the Enzo would travel approximately 330 meters in 11 seconds. Thus, the correct answer is option 'B'.