A submarine is inspecting the surface of the water with a laser that p...
This question is testing our understanding of total internal reflection. As the laser beam travels from water to air—that is, from a higher to a lower index of refraction—the angle of refraction increases. At the critical angle (θ
c), the angle of refraction becomes 90°; at this point, the refracted ray is parallel to the surface of the water. When the angle of incidence is greater than the critical angle, all the light is reflected back into the water. The question is asking for the critical angle:

The inverse sine of 0.75 must be slightly higher than

48.59° is the exact answer.
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A submarine is inspecting the surface of the water with a laser that p...
Understanding the concept:
When a laser beam travels from one medium to another, it can either be refracted, reflected, or transmitted depending on the angle of incidence and the refractive indices of the two media. In this case, the laser beam is traveling from the submarine through the air to the surface of the water.
Explanation:
To calculate the critical angle at which the laser beam will be totally internally reflected back into the water, we can use Snell's Law:
n1 * sin(theta1) = n2 * sin(theta2)
Given that n1 (refractive index of air) = 1 and n2 (refractive index of water) = 1.33, and since the laser beam will be totally internally reflected, the angle of refraction in air will be 90 degrees.
sin(theta1) = n2 / n1
sin(theta1) = 1.33 / 1
sin(theta1) = 1.33
Therefore, the critical angle theta1 = sin^(-1)(1.33) = 49 degrees.
Conclusion:
So, the angle at which the laser will not penetrate the surface of the water but rather reflect entirely back into the water is 49 degrees. This means that any angle greater than 49 degrees will result in total internal reflection of the laser beam.