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If P(A) = 7/11, P(B) = 6 / 11 and P(A∪B) = 8/11, then P(A|B) = ________

  • a)

  • b)
    2/3

  • c)
    1/2

  • d)
    5/6

Correct answer is option 'D'. Can you explain this answer?
Verified Answer
If P(A) = 7/11, P(B) = 6 / 11 and P(A∪B) = 8/11, then P(A|B) = ___...
We know that P(A|B) = P(A∩B) / P(B). (By formula for conditional probability)
Also P(A∪B) = P(A)+P(B) – P(A∩B). (By formula of probability)
⇒ 8/11 = 7/11 + 6/11 – P(A∩B)
⇒ P(A∩B) = 13/11 – 7/11
⇒ P(A∩B) = 6/11
P(A|B) = (6/11) / (6/11).
P(A|B) = 1.
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Most Upvoted Answer
If P(A) = 7/11, P(B) = 6 / 11 and P(A∪B) = 8/11, then P(A|B) = ___...
Understanding the Problem
To find P(A|B), we can use the formula for conditional probability:
P(A|B) = P(A ∩ B) / P(B)
Where:
- P(A|B) is the probability of A given B.
- P(A ∩ B) is the probability of both A and B occurring.
- P(B) is the probability of B.
Given Values
- P(A) = 7/11
- P(B) = 6/11
- P(A ∪ B) = 8/11
Finding P(A ∩ B)
Using the formula for the union of two events:
P(A ∪ B) = P(A) + P(B) - P(A ∩ B)
We can rearrange this to find P(A ∩ B):
P(A ∩ B) = P(A) + P(B) - P(A ∪ B)
Now substituting the provided values:
P(A ∩ B) = (7/11) + (6/11) - (8/11)
Calculating P(A ∩ B)
- Combine the fractions:
P(A ∩ B) = (7 + 6 - 8) / 11
P(A ∩ B) = 5/11
Calculating P(A|B)
Now, substitute P(A ∩ B) and P(B) into the conditional probability formula:
P(A|B) = P(A ∩ B) / P(B)
P(A|B) = (5/11) / (6/11)
This simplifies to:
P(A|B) = 5/6
Conclusion
The correct answer is option 'D' (5/6). This indicates that given event B has occurred, the probability of event A occurring is 5/6.
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If P(A) = 7/11, P(B) = 6 / 11 and P(A∪B) = 8/11, then P(A|B) = ________a)1b)2/3c)1/2d)5/6Correct answer is option 'D'. Can you explain this answer?
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