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Conductometric titration curve of an equimolar mixture of HCl and HCN with NaOH (aq) can be given as
- a)
- b)
- c)
- d)
Correct answer is option 'D'. Can you explain this answer?
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Conductometric titration curve of an equimolar mixture of HCl and HCN ...
The titration is an example of titration of mixture of acids against strong base (NaOH).
When mixture of acid is titrated with NaOH, strong acid will react first followed by weak acid.
Here, HCl will react with NaOH in the start and get neutralised.
The neutralised reaction is,
HCl + NaOH → NaCl + H2O
During this reaction, the conductance of the solution gradually decreases due to the removal of H+ ions of highly ionised HCl to form unionised water.
This will be the first part of the graph.
When HCl is finished HCN starts reacting with NaOH. Here, the neutralisation reaction is
HCN + NaOH → NaCN + H2O
HCN + NaOH → NaCN + H2O
During the neutralisation of weak acid the conductance increases marginally due to the salts (NaCN) produced which will be the second part of graph.
After the equivalence point, the increase in conductance is appreciable due to the added OH− ions.
Thus, the conductance will decrease steeply and then increase marginally and again increase steeply.
Thus, option (d) is correct.
Thus, option (d) is correct.
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