Computer Science Engineering (CSE) Exam > Computer Science Engineering (CSE) Questions > Consider a relation R(A,B,C,D,E) with the fol...
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Consider a relation R(A,B,C,D,E) with the following functional dependencies:
ABC -> DE and
D -> AB
The number of superkeys of R is:
D -> AB
The number of superkeys of R is:
- a)2
- b)7
- c)12
- d)10
Correct answer is option 'D'. Can you explain this answer?
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Consider a relation R(A,B,C,D,E) with the following functional depende...
A superkey is a combination of columns that uniquely identifies any row within a relational database management system (RDBMS) table.
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Consider a relation R(A,B,C,D,E) with the following functional depende...
DE, BD - AE, E - C.
To find the candidate keys for this relation, we can start by finding the closure of each attribute.
The closure of A is {A}.
The closure of B is {B}.
The closure of C is {C}.
The closure of D is {D, E, C}.
The closure of E is {E, C}.
Since the closure of D includes all the attributes, D is a candidate key.
To check if there are any other candidate keys, we need to remove D from consideration and find the closure of the remaining attributes.
Removing D, we have the following functional dependencies: ABC - DE, BD - AE, E - C.
The closure of A is {A}.
The closure of B is {B}.
The closure of C is {C}.
The closure of E is {E, C}.
Since the closure of A, B, C, and E do not include all the attributes, there are no other candidate keys.
Therefore, the candidate key for this relation is D.
To find the candidate keys for this relation, we can start by finding the closure of each attribute.
The closure of A is {A}.
The closure of B is {B}.
The closure of C is {C}.
The closure of D is {D, E, C}.
The closure of E is {E, C}.
Since the closure of D includes all the attributes, D is a candidate key.
To check if there are any other candidate keys, we need to remove D from consideration and find the closure of the remaining attributes.
Removing D, we have the following functional dependencies: ABC - DE, BD - AE, E - C.
The closure of A is {A}.
The closure of B is {B}.
The closure of C is {C}.
The closure of E is {E, C}.
Since the closure of A, B, C, and E do not include all the attributes, there are no other candidate keys.
Therefore, the candidate key for this relation is D.
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Consider a relation R(A,B,C,D,E) with the following functional dependencies:ABC -> DE andD -> ABThe number of superkeys of R is:a)2b)7c)12d)10Correct answer is option 'D'. Can you explain this answer?
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