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A voltage v (t) = 100sinωt is applied to a circuit. The current flowing through the circuit is i(t) = 15sin(ωt-30⁰). Determine the average power delivered to the circuit.
- a)620
- b)630
- c)640
- d)650
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
A voltage v (t) = 100sinωt is applied to a circuit. The current ...
The expression of average power delivered to the circuit is Pavg = VeffIeffcosθ, θ = 30⁰. We have Veff = 71, Ieff = 11. So the average power delivered to the circuit Pavg = 71 x 11 x cos 30⁰ = 650W.
Most Upvoted Answer
A voltage v (t) = 100sinωt is applied to a circuit. The current ...
Calculation of Power
- The average power delivered to the circuit can be calculated using the formula: P_avg = (1/2)Vpk * Ipk * cos(θ)
- Where Vpk is the peak voltage (100V), Ipk is the peak current (15A), and θ is the phase angle between the voltage and current.
Calculating θ
- The phase angle between the voltage and current can be found by subtracting the phase angle of the current from the phase angle of the voltage.
- θ = 0° - (-30°) = 30°
Calculating Power
- P_avg = (1/2)(100)(15)cos(30°) = 650W
Therefore, the average power delivered to the circuit is 650W. Hence, the correct answer is option 'D'.
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