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In case of purely resistive circuit, the average power is?
- a)VmIm
- b)VmIm/2
- c)VmIm/4
- d)VmIm/8
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
In case of purely resistive circuit, the average power is?a)VmImb)VmIm...
In case of purely resistive circuit, the phase angle between the voltage and current is zero that is θ=0⁰. Hence the average power = VmIm/2.
Most Upvoted Answer
In case of purely resistive circuit, the average power is?a)VmImb)VmIm...
Explanation:
Average power in a purely resistive circuit can be calculated using the formula P = VmImcosφ, where Vm is the peak voltage, Im is the peak current, and φ is the phase angle between the voltage and current waveforms.
Given that the phase angle is 0 degrees, the formula simplifies to P = VmIm. To find the average power, we need to divide this value by 2 since power is proportional to the square of the voltage or current.
Therefore, the average power in a purely resistive circuit is VmIm/2, which is option B.
Average power in a purely resistive circuit can be calculated using the formula P = VmImcosφ, where Vm is the peak voltage, Im is the peak current, and φ is the phase angle between the voltage and current waveforms.
- Peak Voltage (Vm): This is the maximum voltage value in the waveform.
- Peak Current (Im): This is the maximum current value in the waveform.
- Phase Angle (φ): In a purely resistive circuit, the voltage and current waveforms are in phase with each other, so the phase angle is 0 degrees.
Given that the phase angle is 0 degrees, the formula simplifies to P = VmIm. To find the average power, we need to divide this value by 2 since power is proportional to the square of the voltage or current.
Therefore, the average power in a purely resistive circuit is VmIm/2, which is option B.
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