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A magnetising force of 800 AT/m will produce a flux density of ______ in air.
  • a)
    1 Wb/m2
  • b)
    1 mWb/m2
  • c)
    10 mWb/m2
  • d)
    0.5 Wb/m2
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
A magnetising force of 800 AT/m will produce a flux density of ______ ...
Concept:
Magnetic field strength or field intensity (H) is the amount of magnetizing force.
Magnetic flux density (B) is the amount of magnetic force induced on the given body due to the magnetizing force H.
The relation between B and H is,
B = μH
Where, 
μ = μ0 μr =  Permeability of the material
μ0 = Absolute permeability = 4π x 10-7 H/m
μr = relative permeability 
Calculation:
Given-
H = 800 AT/m , μr = 1 (∵ for air)
So that flux density for given magnetising force will be
B = 4π x 10-7 x 800 = 1.0053 x 10-3
B ≈ 1 mWb/m2
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Community Answer
A magnetising force of 800 AT/m will produce a flux density of ______ ...
Calculation of flux density in air
Flux density (B) is given by the formula B = μ0 * H, where μ0 is the permeability of free space (4π x 10^-7 H/m) and H is the magnetising force in amperes per meter (A/m).
Given that the magnetising force is 800 AT/m, we can calculate the flux density in air as follows:
B = μ0 * H
B = 4π x 10^-7 * 800
B = 3.183 * 10^-4 T

Conversion to mWb/m2
To convert the flux density from Tesla (T) to milliWeber per square meter (mWb/m2), we use the formula 1 T = 1 Wb/m2. Therefore, we have:
B = 3.183 * 10^-4 T
B = 3.183 * 10^-4 Wb/m2
B = 318.3 mWb/m2
Therefore, the flux density in air produced by a magnetising force of 800 AT/m is 318.3 mWb/m2, which is closest to option (b) 1 mWb/m2.
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A magnetising force of 800 AT/m will produce a flux density of ______ in air.a)1 Wb/m2b)1 mWb/m2c)10 mWb/m2d)0.5 Wb/m2Correct answer is option 'B'. Can you explain this answer?
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