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A ball is being rotated in a circle of radius 5 m with a constant tangential velocity of 20 m/s. A stone is also being rotated in a circle of radius 4 m with a constant tangential velocity of 16 m/s. Which one of the following choices is true about both the circular motions?
  • a)
    Both have same angular velocity
  • b)
    Both have different angular velocity
  • c)
    Angular velocity of ball > angular velocity of stone
  • d)
    Angular velocity of stone > angular velocity of ball
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
A ball is being rotated in a circle of radius 5 m with a constant tang...
Angular velocity = Tangential velocity/Radius. When we put in the values and calculate the angular velocities for each of the circular motions, we see that both the angular velocities are equal to each other and the value is 4 rad/s.
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A ball is being rotated in a circle of radius 5 m with a constant tang...
Radius =5m. velocity= 20m/sec. u draw a circle and label them 2 circle
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A ball is being rotated in a circle of radius 5 m with a constant tang...
A) Both have same angular velocity
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Directions:Read the passages and choose the best answer to each question.PassageStudents debate 4 hypotheses regarding the origin of the asteroid belt located between Mars and Jupiter, based on the following observations.ObservationsObservation 1- If all of the asteroids were gathered together into one object, the diameter of the object formed would be less than half the diameter of Earth’s Moon.Observation 2- The total mass of the asteroid belt is only 4% that of the Moon. One asteroid alone, Ceres, contains 1/3 of the total mass of the asteroid belt.Observation 3- Asteroids are largely composed of silicate, with some deposits of iron and nickel, a composition proportionately similar to that of the terrestrial planets.Some asteroids also contain carbon and other elements.Observation 4- There is a strong orbital resonance (overlapping gravity) with Jupiter in the region of the asteroid belt, which keeps the asteroids in an orbit around the sun.Observation 5- In reality, asteroids within the belt are very far apart, not clustered together.Observation 6- Within the early solar system, the velocity of collisions within the region of the asteroid belt was much higher than it is currently.Hypothesis 1All of the material that makes up the asteroids in the asteroid belt is similar to that of the material that makes up the terrestrial planets. The velocity of collisions in the early solar system was at one time high enough to break apart planets as they formed. Since one asteroid, Ceres, has 1/3 the total mass of the belt, the asteroids are most likely the result of a partially formed planet that broke apart and became trapped in an orbit between Mars and Jupiter.Hypothesis 2 The material that composes the asteroids is similar to that of the terrestrial planets. The belt likely formed during the same time that the planets were forming, and due to the strong orbital resonance with the gas giant Jupiter and high velocity collisions, chunks of the material were pulled away from various planets and trapped within orbit. This also explains the varying composition of the asteroids throughout the belt.Hypothesis 3 The asteroids could not once have been a planet, because there is not enough material within the entire belt to form a planet-sized object. The lack of material, shown by the total diameter and mass of the objects within the belt, is proof that the asteroids are no more than large particles left over from the formation of the terrestrial planets from a single cloud of material.Hypothesis 4 The asteroids most likely came from somewhere outside the solar system. As they passed through space at varying intervals, they were trapped by the large orbital resonance of Jupiter and formed a “belt.” The vast distances between most of the asteroids in the belt are evidence that they did not come from a singular source, but arrived at different points in the belt’s development.Q. Suppose that supporters of Hypothesis 2 suggested that the asteroid belt, when it was first formed, contained dense formations of ice and debris slightly bigger than current asteroids. Which of the following statements about the asteroids’ composition would be most consistent with their suggestion?

Directions:Read the passages and choose the best answer to each question.PassageNear the end of the 19th century, British engineer Osborne Reynolds ran a set of experiments to observe and predict the transition between laminar (steady) and turbulent flow of a liquid through a pipe. In Reynolds’ experiments, dye was forced through a liquid to show visually when the flow changed from laminar to turbulent. Laminar flow is common only in cases in which the flow channel is relatively small, the fluid is moving slowly, and its viscosity (the degree to which a fluid resists flow under an applied forc e) is relatively high. In turbulent flow, the speed of the fluid at any given point is continuously undergoing changes in both magnitude and direction. Reynolds demonstrated that the transition from laminar to turbulent flow in a pipe depends upon the value of a mathematical quantity equal to the velocity of flow (V ) times the diameter of the tube (D) times the mass density (ρ) of the fluid divided by its absolute viscosity (µ). The “Reynolds number,” as it is called, is determined by the following equation:Several students designed similar experiments to observe flow rates of different liquids. To conduct the experiments, the students were given the following apparatus: Liquid supply tank with clear test section tube and ‘bell mouth’ entrance 1 Rotameter to measure the velocity of flow (flow rate) Tap water • Motor oil 4, 10-ft long smooth pipes of various diameters: 0.25-inch, 0.50-inch, 0.75-inch, 1.0-inchFigure 1 illustrates an approximation of the set-up of each experiment.Figure 2 shows approximate viscosities of the water and motor oils used in the experiments.Experiment 1In Experiment 1, students began with a pipe of diameter 0.25 inches. The pipe was set first at a 15° angle and tap water was released steadily from the tank into the pipe. The velocity of flow (V) was measured. The pipe was then set at a 30° angle, a 45° angle, and a 60° angle, water was released steadily from the tank into the pipe, and the velocity of flow was measured. The process was then repeated for each diameter of pipe using the same amount of water each time. All data were recorded in Table 1. Temperature of the water was held constant at 20°C.Experiment 2In the second experiment, the tap water was replaced by Motor Oil A and the processes were repeated. The results are given in Table 2.Experiment 3In a third experiment, the tap water was replaced by Motor Oil B and the processes were repeated.Q.Which of the following conclusions is best supported by information in the passage? As viscosity increases

Directions:Read the passages and choose the best answer to each question.PassageNear the end of the 19th century, British engineer Osborne Reynolds ran a set of experiments to observe and predict the transition between laminar (steady) and turbulent flow of a liquid through a pipe. In Reynolds’ experiments, dye was forced through a liquid to show visually when the flow changed from laminar to turbulent. Laminar flow is common only in cases in which the flow channel is relatively small, the fluid is moving slowly, and its viscosity (the degree to which a fluid resists flow under an applied forc e) is relatively high. In turbulent flow, the speed of the fluid at any given point is continuously undergoing changes in both magnitude and direction. Reynolds demonstrated that the transition from laminar to turbulent flow in a pipe depends upon the value of a mathematical quantity equal to the velocity of flow (V ) times the diameter of the tube (D) times the mass density (ρ) of the fluid divided by its absolute viscosity (µ). The “Reynolds number,” as it is called, is determined by the following equation:Several students designed similar experiments to observe flow rates of different liquids. To conduct the experiments, the students were given the following apparatus: Liquid supply tank with clear test section tube and ‘bell mouth’ entrance 1 Rotameter to measure the velocity of flow (flow rate) Tap water • Motor oil 4, 10-ft long smooth pipes of various diameters: 0.25-inch, 0.50-inch, 0.75-inch, 1.0-inchFigure 1 illustrates an approximation of the set-up of each experiment.Figure 2 shows approximate viscosities of the water and motor oils used in the experiments.Experiment 1In Experiment 1, students began with a pipe of diameter 0.25 inches. The pipe was set first at a 15° angle and tap water was released steadily from the tank into the pipe. The velocity of flow (V) was measured. The pipe was then set at a 30° angle, a 45° angle, and a 60° angle, water was released steadily from the tank into the pipe, and the velocity of flow was measured. The process was then repeated for each diameter of pipe using the same amount of water each time. All data were recorded in Table 1. Temperature of the water was held constant at 20°C.Experiment 2In the second experiment, the tap water was replaced by Motor Oil A and the processes were repeated. The results are given in Table 2.Experiment 3In a third experiment, the tap water was replaced by Motor Oil B and the processes were repeated.Q.Based on Experiment 1, the relationship between the angle of the pipe and the velocity of flow

Directions:Read the passages and choose the best answer to each question.PassageNear the end of the 19th century, British engineer Osborne Reynolds ran a set of experiments to observe and predict the transition between laminar (steady) and turbulent flow of a liquid through a pipe. In Reynolds’ experiments, dye was forced through a liquid to show visually when the flow changed from laminar to turbulent. Laminar flow is common only in cases in which the flow channel is relatively small, the fluid is moving slowly, and its viscosity (the degree to which a fluid resists flow under an applied forc e) is relatively high. In turbulent flow, the speed of the fluid at any given point is continuously undergoing changes in both magnitude and direction. Reynolds demonstrated that the transition from laminar to turbulent flow in a pipe depends upon the value of a mathematical quantity equal to the velocity of flow (V ) times the diameter of the tube (D) times the mass density (ρ) of the fluid divided by its absolute viscosity (µ). The “Reynolds number,” as it is called, is determined by the following equation:Several students designed similar experiments to observe flow rates of different liquids. To conduct the experiments, the students were given the following apparatus: Liquid supply tank with clear test section tube and ‘bell mouth’ entrance 1 Rotameter to measure the velocity of flow (flow rate) Tap water • Motor oil 4, 10-ft long smooth pipes of various diameters: 0.25-inch, 0.50-inch, 0.75-inch, 1.0-inchFigure 1 illustrates an approximation of the set-up of each experiment.Figure 2 shows approximate viscosities of the water and motor oils used in the experiments.Experiment 1In Experiment 1, students began with a pipe of diameter 0.25 inches. The pipe was set first at a 15° angle and tap water was released steadily from the tank into the pipe. The velocity of flow (V) was measured. The pipe was then set at a 30° angle, a 45° angle, and a 60° angle, water was released steadily from the tank into the pipe, and the velocity of flow was measured. The process was then repeated for each diameter of pipe using the same amount of water each time. All data were recorded in Table 1. Temperature of the water was held constant at 20°C.Experiment 2In the second experiment, the tap water was replaced by Motor Oil A and the processes were repeated. The results are given in Table 2.Experiment 3In a third experiment, the tap water was replaced by Motor Oil B and the processes were repeated.Q.According to the passage, laminar flow was most likely to be observed under which of the following conditions?

Directions:Read the passages and choose the best answer to each question.PassageNear the end of the 19th century, British engineer Osborne Reynolds ran a set of experiments to observe and predict the transition between laminar (steady) and turbulent flow of a liquid through a pipe. In Reynolds’ experiments, dye was forced through a liquid to show visually when the flow changed from laminar to turbulent. Laminar flow is common only in cases in which the flow channel is relatively small, the fluid is moving slowly, and its viscosity (the degree to which a fluid resists flow under an applied forc e) is relatively high. In turbulent flow, the speed of the fluid at any given point is continuously undergoing changes in both magnitude and direction. Reynolds demonstrated that the transition from laminar to turbulent flow in a pipe depends upon the value of a mathematical quantity equal to the velocity of flow (V ) times the diameter of the tube (D) times the mass density (ρ) of the fluid divided by its absolute viscosity (µ). The “Reynolds number,” as it is called, is determined by the following equation:Several students designed similar experiments to observe flow rates of different liquids. To conduct the experiments, the students were given the following apparatus: Liquid supply tank with clear test section tube and ‘bell mouth’ entrance 1 Rotameter to measure the velocity of flow (flow rate) Tap water • Motor oil 4, 10-ft long smooth pipes of various diameters: 0.25-inch, 0.50-inch, 0.75-inch, 1.0-inchFigure 1 illustrates an approximation of the set-up of each experiment.Figure 2 shows approximate viscosities of the water and motor oils used in the experiments.Experiment 1In Experiment 1, students began with a pipe of diameter 0.25 inches. The pipe was set first at a 15° angle and tap water was released steadily from the tank into the pipe. The velocity of flow (V) was measured. The pipe was then set at a 30° angle, a 45° angle, and a 60° angle, water was released steadily from the tank into the pipe, and the velocity of flow was measured. The process was then repeated for each diameter of pipe using the same amount of water each time. All data were recorded in Table 1. Temperature of the water was held constant at 20°C.Experiment 2In the second experiment, the tap water was replaced by Motor Oil A and the processes were repeated. The results are given in Table 2.Experiment 3In a third experiment, the tap water was replaced by Motor Oil B and the processes were repeated.Q.Information in the passage and the results of the experiments indicate which of the following? Compared to tap water, Motor Oil A

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A ball is being rotated in a circle of radius 5 m with a constant tangential velocity of 20 m/s. A stone is also being rotated in a circle of radius 4 m with a constant tangential velocity of 16 m/s. Which one of the following choices is true about both the circular motions?a)Both have same angular velocityb)Both have different angular velocityc)Angular velocity of ball > angular velocity of stoned)Angular velocity of stone > angular velocity of ballCorrect answer is option 'A'. Can you explain this answer?
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A ball is being rotated in a circle of radius 5 m with a constant tangential velocity of 20 m/s. A stone is also being rotated in a circle of radius 4 m with a constant tangential velocity of 16 m/s. Which one of the following choices is true about both the circular motions?a)Both have same angular velocityb)Both have different angular velocityc)Angular velocity of ball > angular velocity of stoned)Angular velocity of stone > angular velocity of ballCorrect answer is option 'A'. Can you explain this answer? for ACT 2025 is part of ACT preparation. The Question and answers have been prepared according to the ACT exam syllabus. Information about A ball is being rotated in a circle of radius 5 m with a constant tangential velocity of 20 m/s. A stone is also being rotated in a circle of radius 4 m with a constant tangential velocity of 16 m/s. Which one of the following choices is true about both the circular motions?a)Both have same angular velocityb)Both have different angular velocityc)Angular velocity of ball > angular velocity of stoned)Angular velocity of stone > angular velocity of ballCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for ACT 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A ball is being rotated in a circle of radius 5 m with a constant tangential velocity of 20 m/s. A stone is also being rotated in a circle of radius 4 m with a constant tangential velocity of 16 m/s. Which one of the following choices is true about both the circular motions?a)Both have same angular velocityb)Both have different angular velocityc)Angular velocity of ball > angular velocity of stoned)Angular velocity of stone > angular velocity of ballCorrect answer is option 'A'. Can you explain this answer?.
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Here you can find the meaning of A ball is being rotated in a circle of radius 5 m with a constant tangential velocity of 20 m/s. A stone is also being rotated in a circle of radius 4 m with a constant tangential velocity of 16 m/s. Which one of the following choices is true about both the circular motions?a)Both have same angular velocityb)Both have different angular velocityc)Angular velocity of ball > angular velocity of stoned)Angular velocity of stone > angular velocity of ballCorrect answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of A ball is being rotated in a circle of radius 5 m with a constant tangential velocity of 20 m/s. A stone is also being rotated in a circle of radius 4 m with a constant tangential velocity of 16 m/s. Which one of the following choices is true about both the circular motions?a)Both have same angular velocityb)Both have different angular velocityc)Angular velocity of ball > angular velocity of stoned)Angular velocity of stone > angular velocity of ballCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for A ball is being rotated in a circle of radius 5 m with a constant tangential velocity of 20 m/s. A stone is also being rotated in a circle of radius 4 m with a constant tangential velocity of 16 m/s. Which one of the following choices is true about both the circular motions?a)Both have same angular velocityb)Both have different angular velocityc)Angular velocity of ball > angular velocity of stoned)Angular velocity of stone > angular velocity of ballCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of A ball is being rotated in a circle of radius 5 m with a constant tangential velocity of 20 m/s. A stone is also being rotated in a circle of radius 4 m with a constant tangential velocity of 16 m/s. Which one of the following choices is true about both the circular motions?a)Both have same angular velocityb)Both have different angular velocityc)Angular velocity of ball > angular velocity of stoned)Angular velocity of stone > angular velocity of ballCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice A ball is being rotated in a circle of radius 5 m with a constant tangential velocity of 20 m/s. A stone is also being rotated in a circle of radius 4 m with a constant tangential velocity of 16 m/s. Which one of the following choices is true about both the circular motions?a)Both have same angular velocityb)Both have different angular velocityc)Angular velocity of ball > angular velocity of stoned)Angular velocity of stone > angular velocity of ballCorrect answer is option 'A'. Can you explain this answer? tests, examples and also practice ACT tests.
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