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A step-up chopper is used to deliver a load voltage of 500 V from a 220 V d.c. source. If the blocking period of the thyristor is 80 μs, the required pulse width is -
- a)50.8 μs
- b)101.8 μs
- c)92.4 μs
- d)152.4 μs
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A step-up chopper is used to deliver a load voltage of 500 V from a 22...
Concept:
The output voltage of a step-up chopper is given by:
where, Vo = Output voltage
Vin = Input voltage
D = Duty cycle
The duty cycle is given by:
TON is the pulse width of the output.
Calculation:
Given, Vo = 500 V
Vin = 220 V
Toff = 80 μs
Most Upvoted Answer
A step-up chopper is used to deliver a load voltage of 500 V from a 22...
Ms, find the duty cycle of the chopper.
The duty cycle of a chopper is defined as the ratio of the ON time of the thyristor to the total time period of one complete cycle. It is given by the formula:
Duty Cycle = (ON time of thyristor) / (Total time period)
In this case, the total time period is the sum of the ON time and the blocking time (t), which is given as 80 ms.
Total time period = ON time + blocking time = ON time + 80 ms
To find the ON time of the thyristor, we need to use the relationship between the load voltage and the input voltage in a step-up chopper, which is given by the formula:
Load voltage / Input voltage = (ON time) / (ON time + blocking time)
In this case, the load voltage is 500 V and the input voltage is 220 V.
500 V / 220 V = (ON time) / (ON time + 80 ms)
Now, we can solve for the ON time:
ON time = (500 V / 220 V) * (ON time + 80 ms)
Simplifying this equation, we get:
ON time = (500 / 220) * (ON time + 80 ms)
ON time = (500 / 220) * ON time + (500 / 220) * 80 ms
ON time - (500 / 220) * ON time = (500 / 220) * 80 ms
ON time * (1 - 500 / 220) = (500 / 220) * 80 ms
ON time * (220 - 500) / 220 = (500 / 220) * 80 ms
ON time * (-280) / 220 = (500 / 220) * 80 ms
ON time = ((500 / 220) * 80 ms) * (220 / -280)
ON time ≈ -0.1273 * 80 ms
ON time ≈ -10.18 ms
Since the ON time cannot be negative, we take the absolute value:
ON time ≈ 10.18 ms
Now, we can calculate the duty cycle:
Duty Cycle = ON time / (ON time + blocking time)
Duty Cycle = 10.18 ms / (10.18 ms + 80 ms)
Duty Cycle ≈ 10.18 ms / 90.18 ms
Duty Cycle ≈ 0.113 or 11.3%
Therefore, the duty cycle of the chopper is approximately 11.3%.
The duty cycle of a chopper is defined as the ratio of the ON time of the thyristor to the total time period of one complete cycle. It is given by the formula:
Duty Cycle = (ON time of thyristor) / (Total time period)
In this case, the total time period is the sum of the ON time and the blocking time (t), which is given as 80 ms.
Total time period = ON time + blocking time = ON time + 80 ms
To find the ON time of the thyristor, we need to use the relationship between the load voltage and the input voltage in a step-up chopper, which is given by the formula:
Load voltage / Input voltage = (ON time) / (ON time + blocking time)
In this case, the load voltage is 500 V and the input voltage is 220 V.
500 V / 220 V = (ON time) / (ON time + 80 ms)
Now, we can solve for the ON time:
ON time = (500 V / 220 V) * (ON time + 80 ms)
Simplifying this equation, we get:
ON time = (500 / 220) * (ON time + 80 ms)
ON time = (500 / 220) * ON time + (500 / 220) * 80 ms
ON time - (500 / 220) * ON time = (500 / 220) * 80 ms
ON time * (1 - 500 / 220) = (500 / 220) * 80 ms
ON time * (220 - 500) / 220 = (500 / 220) * 80 ms
ON time * (-280) / 220 = (500 / 220) * 80 ms
ON time = ((500 / 220) * 80 ms) * (220 / -280)
ON time ≈ -0.1273 * 80 ms
ON time ≈ -10.18 ms
Since the ON time cannot be negative, we take the absolute value:
ON time ≈ 10.18 ms
Now, we can calculate the duty cycle:
Duty Cycle = ON time / (ON time + blocking time)
Duty Cycle = 10.18 ms / (10.18 ms + 80 ms)
Duty Cycle ≈ 10.18 ms / 90.18 ms
Duty Cycle ≈ 0.113 or 11.3%
Therefore, the duty cycle of the chopper is approximately 11.3%.
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A step-up chopper is used to deliver a load voltage of 500 V from a 220 V d.c. source. If the blocking period of the thyristor is 80 μs, the required pulse width is -a)50.8 μsb)101.8 μsc)92.4 μsd)152.4 μsCorrect answer is option 'B'. Can you explain this answer? for Electrical Engineering (EE) 2025 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A step-up chopper is used to deliver a load voltage of 500 V from a 220 V d.c. source. If the blocking period of the thyristor is 80 μs, the required pulse width is -a)50.8 μsb)101.8 μsc)92.4 μsd)152.4 μsCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A step-up chopper is used to deliver a load voltage of 500 V from a 220 V d.c. source. If the blocking period of the thyristor is 80 μs, the required pulse width is -a)50.8 μsb)101.8 μsc)92.4 μsd)152.4 μsCorrect answer is option 'B'. Can you explain this answer?.
A step-up chopper is used to deliver a load voltage of 500 V from a 220 V d.c. source. If the blocking period of the thyristor is 80 μs, the required pulse width is -a)50.8 μsb)101.8 μsc)92.4 μsd)152.4 μsCorrect answer is option 'B'. Can you explain this answer? for Electrical Engineering (EE) 2025 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A step-up chopper is used to deliver a load voltage of 500 V from a 220 V d.c. source. If the blocking period of the thyristor is 80 μs, the required pulse width is -a)50.8 μsb)101.8 μsc)92.4 μsd)152.4 μsCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A step-up chopper is used to deliver a load voltage of 500 V from a 220 V d.c. source. If the blocking period of the thyristor is 80 μs, the required pulse width is -a)50.8 μsb)101.8 μsc)92.4 μsd)152.4 μsCorrect answer is option 'B'. Can you explain this answer?.
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