Electrical Engineering (EE) Exam  >  Electrical Engineering (EE) Questions  >  The equation of instantaneous power is?a)P (t... Start Learning for Free
The equation of instantaneous power is?
  • a)
    P (t) = (VmIm/2)(cos⁡(2ωt + θ) + sin⁡θ)
  • b)
    P (t) = (VmIm/2)(sin⁡(2ωt + θ) + cos⁡θ)
  • c)
    P (t) = (VmIm/2)(cos⁡(2ωt + θ) + cos⁡θ)
  • d)
    P (t) = (VmIm/2)(sin⁡(2ωt + θ) + sin⁡θ)
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
The equation of instantaneous power is?a)P (t) = (VmIm/2)(cos(2ω...
The equation of instantaneous power is P (t) = (VmIm/2)(cos⁡(2ωt + θ) + cos⁡θ). It consists of two parts. One is a fixed part and the other is time varying which has frequency twice that of the voltage or current wave forms.
View all questions of this test
Most Upvoted Answer
The equation of instantaneous power is?a)P (t) = (VmIm/2)(cos(2ω...
Understanding Instantaneous Power
Instantaneous power in electrical circuits, particularly in AC systems, is defined as the product of voltage and current at a specific moment in time. For sinusoidal voltages and currents, this can be expressed mathematically.
General Formula
For a voltage V(t) and current I(t) that are sinusoidal:
- V(t) = Vm * cos(ωt + φ)
- I(t) = Im * cos(ωt + θ)
Where:
- Vm and Im are the maximum values of voltage and current,
- ω is the angular frequency,
- φ is the phase angle of voltage,
- θ is the phase angle of current.
Calculating Instantaneous Power
The instantaneous power P(t) can be calculated as:
- P(t) = V(t) * I(t)
Substituting the expressions for V(t) and I(t):
- P(t) = Vm * cos(ωt + φ) * Im * cos(ωt + θ)
Using trigonometric identities, we can simplify this expression.
Why Option C is Correct
In the context of the given options:
- The correct formula for instantaneous power includes terms that result from the multiplication of the sinusoidal functions, including the cosine of the sum of angles.
- The option C formulation captures the behavior of the power over time effectively, demonstrating the influence of both voltage and current phase angles on instantaneous power.
Conclusion
Thus, the correct answer, option C, reflects the proper derivation and relationship of voltage and current in terms of instantaneous power, which can be expressed as:
P(t) = (VmIm/2)(cos(2ωt + (φ + θ)) + cos(φ - θ))
This formula shows how instantaneous power varies with time based on the interactions of voltage and current waveforms.
Explore Courses for Electrical Engineering (EE) exam

Top Courses for Electrical Engineering (EE)

Question Description
The equation of instantaneous power is?a)P (t) = (VmIm/2)(cos(2ωt + θ) + sinθ)b)P (t) = (VmIm/2)(sin(2ωt + θ) + cosθ)c)P (t) = (VmIm/2)(cos(2ωt + θ) + cosθ)d)P (t) = (VmIm/2)(sin(2ωt + θ) + sinθ)Correct answer is option 'C'. Can you explain this answer? for Electrical Engineering (EE) 2025 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about The equation of instantaneous power is?a)P (t) = (VmIm/2)(cos(2ωt + θ) + sinθ)b)P (t) = (VmIm/2)(sin(2ωt + θ) + cosθ)c)P (t) = (VmIm/2)(cos(2ωt + θ) + cosθ)d)P (t) = (VmIm/2)(sin(2ωt + θ) + sinθ)Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The equation of instantaneous power is?a)P (t) = (VmIm/2)(cos(2ωt + θ) + sinθ)b)P (t) = (VmIm/2)(sin(2ωt + θ) + cosθ)c)P (t) = (VmIm/2)(cos(2ωt + θ) + cosθ)d)P (t) = (VmIm/2)(sin(2ωt + θ) + sinθ)Correct answer is option 'C'. Can you explain this answer?.
Solutions for The equation of instantaneous power is?a)P (t) = (VmIm/2)(cos(2ωt + θ) + sinθ)b)P (t) = (VmIm/2)(sin(2ωt + θ) + cosθ)c)P (t) = (VmIm/2)(cos(2ωt + θ) + cosθ)d)P (t) = (VmIm/2)(sin(2ωt + θ) + sinθ)Correct answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Electrical Engineering (EE). Download more important topics, notes, lectures and mock test series for Electrical Engineering (EE) Exam by signing up for free.
Here you can find the meaning of The equation of instantaneous power is?a)P (t) = (VmIm/2)(cos(2ωt + θ) + sinθ)b)P (t) = (VmIm/2)(sin(2ωt + θ) + cosθ)c)P (t) = (VmIm/2)(cos(2ωt + θ) + cosθ)d)P (t) = (VmIm/2)(sin(2ωt + θ) + sinθ)Correct answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of The equation of instantaneous power is?a)P (t) = (VmIm/2)(cos(2ωt + θ) + sinθ)b)P (t) = (VmIm/2)(sin(2ωt + θ) + cosθ)c)P (t) = (VmIm/2)(cos(2ωt + θ) + cosθ)d)P (t) = (VmIm/2)(sin(2ωt + θ) + sinθ)Correct answer is option 'C'. Can you explain this answer?, a detailed solution for The equation of instantaneous power is?a)P (t) = (VmIm/2)(cos(2ωt + θ) + sinθ)b)P (t) = (VmIm/2)(sin(2ωt + θ) + cosθ)c)P (t) = (VmIm/2)(cos(2ωt + θ) + cosθ)d)P (t) = (VmIm/2)(sin(2ωt + θ) + sinθ)Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of The equation of instantaneous power is?a)P (t) = (VmIm/2)(cos(2ωt + θ) + sinθ)b)P (t) = (VmIm/2)(sin(2ωt + θ) + cosθ)c)P (t) = (VmIm/2)(cos(2ωt + θ) + cosθ)d)P (t) = (VmIm/2)(sin(2ωt + θ) + sinθ)Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice The equation of instantaneous power is?a)P (t) = (VmIm/2)(cos(2ωt + θ) + sinθ)b)P (t) = (VmIm/2)(sin(2ωt + θ) + cosθ)c)P (t) = (VmIm/2)(cos(2ωt + θ) + cosθ)d)P (t) = (VmIm/2)(sin(2ωt + θ) + sinθ)Correct answer is option 'C'. Can you explain this answer? tests, examples and also practice Electrical Engineering (EE) tests.
Explore Courses for Electrical Engineering (EE) exam

Top Courses for Electrical Engineering (EE)

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev