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The standard heat of combustion of carbon(s), sulphur(s) and carbon disulphide(l) are – 390, – 290 and – 1100 kJ/mol respectively. The standard heat of formation of carbon disulphide (l) is -
  • a)
    – 130 kJ mol–1
  • b)
    + 130 kJ mol–1
  • c)
    – 420 kJ mol–1
  • d)
    + 420 kJ mol–1
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
The standard heat of combustion of carbon(s), sulphur(s) and carbon di...
Understanding Standard Heats of Combustion and Formation
The standard heat of combustion values given for carbon, sulfur, and carbon disulfide are crucial in determining the standard heat of formation of carbon disulfide.
Given Values:
- Heat of combustion of carbon(s): –390 kJ/mol
- Heat of combustion of sulfur(s): –290 kJ/mol
- Heat of combustion of carbon disulfide(l): –1100 kJ/mol
Formation Reaction of Carbon Disulfide:
The formation of carbon disulfide from its elements can be represented as:
C(s) + 2S(s) → CS2(l)
Applying Hess's Law:
Using Hess's Law, we can relate the heats of combustion to the heat of formation:
1. Heat of combustion of products (CS2): –1100 kJ/mol
2. Heat of combustion of reactants (C and S):
- For C: –390 kJ/mol
- For 2 moles of S: 2 × (–290 kJ/mol) = –580 kJ/mol
Calculation of Heat of Formation:
The standard heat of formation (ΔHf) can be calculated using the equation:
ΔHf (CS2) = ΔHc (Reactants) - ΔHc (Products)
Substituting the values:
ΔHf (CS2) = [–390 + (–580)] - (–1100)
This simplifies to:
ΔHf (CS2) = –970 + 1100 = +130 kJ/mol
Conclusion:
Therefore, the standard heat of formation of carbon disulfide (l) is +130 kJ/mol, confirming that the correct answer is option 'B'.
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Community Answer
The standard heat of combustion of carbon(s), sulphur(s) and carbon di...
C(s) + 2S(s) → CS2(l)
ΔfH° = -390 - (290) × 2 - (-1100)
= + 130 kJ mol-1
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The standard heat of combustion of carbon(s), sulphur(s) and carbon disulphide(l) are – 390, – 290 and – 1100 kJ/mol respectively. The standard heat of formation of carbon disulphide (l) is -a)– 130 kJ mol–1b)+ 130 kJ mol–1c)– 420 kJ mol–1d)+ 420 kJ mol–1Correct answer is option 'B'. Can you explain this answer?
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The standard heat of combustion of carbon(s), sulphur(s) and carbon disulphide(l) are – 390, – 290 and – 1100 kJ/mol respectively. The standard heat of formation of carbon disulphide (l) is -a)– 130 kJ mol–1b)+ 130 kJ mol–1c)– 420 kJ mol–1d)+ 420 kJ mol–1Correct answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The standard heat of combustion of carbon(s), sulphur(s) and carbon disulphide(l) are – 390, – 290 and – 1100 kJ/mol respectively. The standard heat of formation of carbon disulphide (l) is -a)– 130 kJ mol–1b)+ 130 kJ mol–1c)– 420 kJ mol–1d)+ 420 kJ mol–1Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The standard heat of combustion of carbon(s), sulphur(s) and carbon disulphide(l) are – 390, – 290 and – 1100 kJ/mol respectively. The standard heat of formation of carbon disulphide (l) is -a)– 130 kJ mol–1b)+ 130 kJ mol–1c)– 420 kJ mol–1d)+ 420 kJ mol–1Correct answer is option 'B'. Can you explain this answer?.
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