A body moves from point A (2,1) to point B (7,13) to point C (15,19). What is the average speed of the body along the given path if the total time taken is 20 s?a)1.15 units/sb)11.5 units/sc)115 units/sd)0.0115 units/sCorrect answer is option 'A'. Can you explain this answer?

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A body moves from point A (2,1) to point B (7,13) to point C (15,19). What is the average speed of the body along the given path if the total time taken is 20 s?

a)
1.15 units/s
b)
11.5 units/s
c)
115 units/s
d)
0.0115 units/s

Correct answer is option 'A'. Can you explain this answer?

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A body moves from point A (2,1) to point B (7,13) to point C (15,19). ...

The distance between A and B is 13 units. The distance between B and C is 10 units. Hence, the total distance is 23 units. The total time taken is 20 s. Average speed = total distance/total time taken = 23/20 = 1.15 units/s.

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A body moves from point A (2,1) to point B (7,13) to point C (15,19). What is the average speed of the body along the given path if the total time taken is 20 s?a)1.15 units/sb)11.5 units/sc)115 units/sd)0.0115 units/sCorrect answer is option 'A'. Can you explain this answer?

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