Wilson starts for office at the same time every day. If he walks at 5 ...
Given information:
- Wilson starts for office at the same time every day.
- If he walks at 5 kmph, he is 2 minutes late.
- If he walks at 10 kmph, he is 4 minutes early.
To find:
- Wilson's correct speed to reach on time.
- The distance to his office.
Assumptions:
- Wilson takes the same route to the office every day.
- The time taken to walk to the office is the same for both speeds.
Solution:
Let's assume the distance to Wilson's office is 'd' km.
Case 1: Walking at 5 kmph
Since Wilson is 2 minutes late, the time taken to walk to the office at 5 kmph is given by:
Time = Distance/Speed = d/5
Case 2: Walking at 10 kmph
Since Wilson is 4 minutes early, the time taken to walk to the office at 10 kmph is given by:
Time = Distance/Speed = d/10
Equation 1:
According to the given information, Wilson takes 2 minutes less than the time taken at 5 kmph.
So, we have the equation: d/10 = d/5 - 2/60
Equation 2:
According to the given information, Wilson takes 4 minutes less than the time taken at 10 kmph.
So, we have the equation: d/5 = d/10 + 4/60
Solving the Equations:
By solving equations 1 and 2, we can find the value of 'd' and Wilson's correct speed.
Multiplying equation 1 by 2, we get: 2d/10 = 2d/5 - 4/60
Simplifying, we have: d/5 = d/5 - 4/60
Combining like terms, we get: 0 = -4/60
This equation has no solution, which means there is no distance 'd' for which Wilson can reach the office on time.
Therefore, it is not possible to determine Wilson's correct speed and the distance to his office based on the given information.