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For the channel shown below if the source generates two symbols m0 and m1 with a probability of 0.6 and 0.4 respectively. The probability of error if the receiver uses MAP coding will be_______(correct up to two decimal places)
Correct answer is between '0.23,0.25'. Can you explain this answer?
Most Upvoted Answer
For the channel shown below if the source generates two symbols m0and ...
If r0 is received:
P(m0) P(r/m0) = 0.6 × 0.6 = 0.36
Also,
P(m1) P(r0­/m1) = 0.4 × 0 = 0
If r1 is received:
P(m0) P (r1/m0) =  (0.6) (0.3)
= 0.18
P(m1­) P(r1/m1)
= (0.4) (0.7)
= 0.28
If r2 is received:
P(m0) P(r2/m0)
(0.6) (0.1)
= 0.06
P(m1) P(r2/m1)
= (0.4) (0.3)
= 0.12
Probability of correct detection
Pc = 0.12 + 0.28 + 0.36
= 0.76
Pe = 1 – 0.76
= 0.24
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For the channel shown below if the source generates two symbols m0and m1with a probability of 0.6 and 0.4 respectively. The probability of error if the receiver uses MAP coding will be_______(correct up to two decimal places)Correct answer is between '0.23,0.25'. Can you explain this answer?
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