There is a balloon filled with a gas at 26-degree centigrade and has a...
As we know that temperature is directly proportional to the volume at constant pressure, 26/39 = 2/ X; so here by equating X equals to 3 liters. Hence required a volume of the balloon at 39 degrees is 3 liters.
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There is a balloon filled with a gas at 26-degree centigrade and has a...
Temperature-Volume Relationship in Gases
The relationship between temperature and volume of a gas is described by Charles's Law, which states that the volume of a gas is directly proportional to its temperature, assuming constant pressure and amount of gas.
Given:
Initial temperature (T1) = 26°C
Initial volume (V1) = 2 liters
Final temperature (T2) = 39°C
Final volume (V2) = ?
Applying Charles's Law, we can write the equation as:
V1 / T1 = V2 / T2
Substituting the given values:
2 / 26 = V2 / 39
Cross-multiplying the equation:
2 × 39 = V2 × 26
Simplifying:
78 = 26V2
Dividing both sides by 26:
V2 = 78 / 26
V2 = 3 liters
Therefore, the volume of the gas inside the balloon when taken to a place with a temperature of 39°C would be 3 liters (option B).
Explanation:
When the temperature of a gas increases, its volume also increases if the pressure and amount of gas remain constant. In this case, the initial volume of the gas inside the balloon is 2 liters at a temperature of 26°C. When the balloon is taken to a place with a higher temperature of 39°C, the volume of the gas inside the balloon increases to 3 liters.
This can be explained by the fact that as the gas molecules gain thermal energy, they move with greater speed and collide more frequently with the walls of the balloon. These collisions exert a greater force on the walls, causing the balloon to expand and the volume to increase.
Therefore, based on the temperature-volume relationship described by Charles's Law, the volume of the gas inside the balloon would be 3 liters at a temperature of 39°C.