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A velocity vector (5m/s) is making and angle of 60 degrees with X axis has a horizonal component of magnitude ___
  • a)
    2.5
  • b)
    5.5
  • c)
    5
  • d)
    10/√3
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
A velocity vector (5m/s) is making and angle of 60 degrees with X axis...
The horizontal component of any vector with magnitude a is a cos θ. Here θ = 60. cos θ = ½. Hence the answer is 5/2 = 2.5 m/s.
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Most Upvoted Answer
A velocity vector (5m/s) is making and angle of 60 degrees with X axis...
Horizontal Component of Velocity Vector
The horizontal component of a velocity vector is given by the magnitude of the velocity vector multiplied by the cosine of the angle it makes with the x-axis.
Given:
Magnitude of velocity vector = 5 m/s
Angle with x-axis = 60 degrees

Calculating Horizontal Component
Horizontal component = 5 m/s * cos(60)
Horizontal component = 5 m/s * 0.5
Horizontal component = 2.5 m/s
Therefore, the horizontal component of the velocity vector is 2.5 m/s.
This means that the velocity vector has a horizontal component of 2.5 m/s in the positive x-direction.
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A velocity vector (5m/s) is making and angle of 60 degrees with X axis has a horizonal component of magnitude ___a)2.5b)5.5c)5d)10/√3Correct answer is option 'A'. Can you explain this answer?
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