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What is the value of the ionic product of water at 298k?
  • a)
    7 x 10-14/mol2L2
  • b)
    1 x 10-10/mol2L2
  • c)
    1 x 10-14/molL2
  • d)
    1 x 10-14/mol2L2
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
What is the value of the ionic product of water at 298k?a)7 x 10-14/mo...
Ionic product is a product of the concentration of hydronium ions and hydroxyl ions in pure water, which remains constant at a particular temperature. It is symbolized as KW and is equal to 1 x 10-14/mol2L2.
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What is the value of the ionic product of water at 298k?a)7 x 10-14/mo...


Calculation of Ionic Product of Water at 298K:

- The ionic product of water (Kw) is the product of the concentrations of H+ ions and OH- ions in water at a specific temperature.
- At 298K, the value of the ionic product of water is 1 x 10^-14 mol^2/L^2.

Explanation:

- The ionic product of water is represented by the equation Kw = [H+][OH-].
- At 298K, the concentration of H+ ions and OH- ions in pure water is approximately 1 x 10^-7 mol/L each.
- Therefore, Kw = (1 x 10^-7)(1 x 10^-7) = 1 x 10^-14 mol^2/L^2.

Importance of Kw:

- The value of the ionic product of water is essential in determining the pH and pOH of a solution.
- It helps in understanding the ionization of water and the behavior of acidic and basic solutions.

In conclusion, the value of the ionic product of water at 298K is 1 x 10^-14 mol^2/L^2. This value is crucial in various chemical calculations and understanding the properties of aqueous solutions.
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