UGC NET Exam > UGC NET Questions > The active medium in a blue LED (light emitti...
Start Learning for Free
The active medium in a blue LED (light emitting diode) is a Gax In1-x N alloy. The band gaps of GaN and InN are 3.5eV and 1.5eV respectively. If the band gap of Gax In1-x N varies approximately linearly with x , the value of x required for the emission of blue light of wavelength 400nm is (take hc ≈ 1200 eV - nm)
- a)0.95
- b)0.75
- c)0.50
- d)0.33
Correct answer is option 'B'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
The active medium in a blue LED (light emitting diode) is a GaxIn1-xN ...
= 1240 eV·nm)
To determine the value of x required for the emission of blue light with a wavelength of 400nm, we need to calculate the corresponding energy.
The energy (E) of a photon is given by the equation E = hc/λ, where h is Planck's constant (6.626 x 10^-34 J·s), c is the speed of light (3 x 10^8 m/s), and λ is the wavelength in meters.
Converting the wavelength from nm to meters: λ = 400nm x (1m/10^9nm) = 4 x 10^-7 m
Calculating the energy: E = (6.626 x 10^-34 J·s) x (3 x 10^8 m/s) / (4 x 10^-7 m) = 4.97 x 10^-19 J
To find the value of x, we can use the linear relationship between the band gap of GaxIn1-xN and x. Let's assume that the band gap (Eg) of GaxIn1-xN is given by the equation Eg = xEg,GaN + (1-x)Eg,InN.
We know that the band gaps of GaN and InN are 3.5eV and 1.5eV respectively.
Substituting the values into the equation: 4.97 x 10^-19 J = x(3.5 eV) + (1-x)(1.5 eV)
Since 1 eV = 1.602 x 10^-19 J, we can convert the energy into eV:
4.97 x 10^-19 J = 4.97 x 10^-19 J / (1.602 x 10^-19 J/eV) = 3.1 eV
Now we can solve for x:
3.1 eV = x(3.5 eV) + (1-x)(1.5 eV)
3.1 eV = 3.5x eV + (1.5 eV - 1.5x eV)
3.1 eV = 3.5x eV + 1.5 eV - 1.5x eV
3.1 eV - 1.5 eV = 3.5x eV - 1.5x eV
1.6 eV = 2x eV
x = 1.6 eV / 2 eV = 0.8
Therefore, the value of x required for the emission of blue light with a wavelength of 400nm is approximately 0.8.
To determine the value of x required for the emission of blue light with a wavelength of 400nm, we need to calculate the corresponding energy.
The energy (E) of a photon is given by the equation E = hc/λ, where h is Planck's constant (6.626 x 10^-34 J·s), c is the speed of light (3 x 10^8 m/s), and λ is the wavelength in meters.
Converting the wavelength from nm to meters: λ = 400nm x (1m/10^9nm) = 4 x 10^-7 m
Calculating the energy: E = (6.626 x 10^-34 J·s) x (3 x 10^8 m/s) / (4 x 10^-7 m) = 4.97 x 10^-19 J
To find the value of x, we can use the linear relationship between the band gap of GaxIn1-xN and x. Let's assume that the band gap (Eg) of GaxIn1-xN is given by the equation Eg = xEg,GaN + (1-x)Eg,InN.
We know that the band gaps of GaN and InN are 3.5eV and 1.5eV respectively.
Substituting the values into the equation: 4.97 x 10^-19 J = x(3.5 eV) + (1-x)(1.5 eV)
Since 1 eV = 1.602 x 10^-19 J, we can convert the energy into eV:
4.97 x 10^-19 J = 4.97 x 10^-19 J / (1.602 x 10^-19 J/eV) = 3.1 eV
Now we can solve for x:
3.1 eV = x(3.5 eV) + (1-x)(1.5 eV)
3.1 eV = 3.5x eV + (1.5 eV - 1.5x eV)
3.1 eV = 3.5x eV + 1.5 eV - 1.5x eV
3.1 eV - 1.5 eV = 3.5x eV - 1.5x eV
1.6 eV = 2x eV
x = 1.6 eV / 2 eV = 0.8
Therefore, the value of x required for the emission of blue light with a wavelength of 400nm is approximately 0.8.
Free Test
FREE
| Start Free Test |
Community Answer
The active medium in a blue LED (light emitting diode) is a GaxIn1-xN ...
We are given with,
EgGoN = 3.5 eV and EglnN = 1.5 eV
Band Gap energy of Gax In1-x N is E ∝ x.
For blue light of wavelength 400nm, the band gap
Thus equating slopes we get;
EgGoN = 3.5 eV and EglnN = 1.5 eV
Band Gap energy of Gax In1-x N is E ∝ x.
For blue light of wavelength 400nm, the band gap
Thus equating slopes we get;
Attention UGC NET Students!
To make sure you are not studying endlessly, EduRev has designed UGC NET study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in UGC NET.
|
Explore Courses for UGC NET exam
|
|
Similar UGC NET Doubts
Top Courses for UGC NETView all
The active medium in a blue LED (light emitting diode) is a GaxIn1-xN alloy. The band gaps of GaN and InN are 3.5eV and 1.5eV respectively. If the band gap of GaxIn1-xN varies approximately linearly with x , the value of x required for the emission of blue light of wavelength 400nm is (take hc ≈ 1200 eV - nm)a)0.95b)0.75c)0.50d)0.33Correct answer is option 'B'. Can you explain this answer?
Question Description
The active medium in a blue LED (light emitting diode) is a GaxIn1-xN alloy. The band gaps of GaN and InN are 3.5eV and 1.5eV respectively. If the band gap of GaxIn1-xN varies approximately linearly with x , the value of x required for the emission of blue light of wavelength 400nm is (take hc ≈ 1200 eV - nm)a)0.95b)0.75c)0.50d)0.33Correct answer is option 'B'. Can you explain this answer? for UGC NET 2024 is part of UGC NET preparation. The Question and answers have been prepared according to the UGC NET exam syllabus. Information about The active medium in a blue LED (light emitting diode) is a GaxIn1-xN alloy. The band gaps of GaN and InN are 3.5eV and 1.5eV respectively. If the band gap of GaxIn1-xN varies approximately linearly with x , the value of x required for the emission of blue light of wavelength 400nm is (take hc ≈ 1200 eV - nm)a)0.95b)0.75c)0.50d)0.33Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for UGC NET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The active medium in a blue LED (light emitting diode) is a GaxIn1-xN alloy. The band gaps of GaN and InN are 3.5eV and 1.5eV respectively. If the band gap of GaxIn1-xN varies approximately linearly with x , the value of x required for the emission of blue light of wavelength 400nm is (take hc ≈ 1200 eV - nm)a)0.95b)0.75c)0.50d)0.33Correct answer is option 'B'. Can you explain this answer?.
The active medium in a blue LED (light emitting diode) is a GaxIn1-xN alloy. The band gaps of GaN and InN are 3.5eV and 1.5eV respectively. If the band gap of GaxIn1-xN varies approximately linearly with x , the value of x required for the emission of blue light of wavelength 400nm is (take hc ≈ 1200 eV - nm)a)0.95b)0.75c)0.50d)0.33Correct answer is option 'B'. Can you explain this answer? for UGC NET 2024 is part of UGC NET preparation. The Question and answers have been prepared according to the UGC NET exam syllabus. Information about The active medium in a blue LED (light emitting diode) is a GaxIn1-xN alloy. The band gaps of GaN and InN are 3.5eV and 1.5eV respectively. If the band gap of GaxIn1-xN varies approximately linearly with x , the value of x required for the emission of blue light of wavelength 400nm is (take hc ≈ 1200 eV - nm)a)0.95b)0.75c)0.50d)0.33Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for UGC NET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The active medium in a blue LED (light emitting diode) is a GaxIn1-xN alloy. The band gaps of GaN and InN are 3.5eV and 1.5eV respectively. If the band gap of GaxIn1-xN varies approximately linearly with x , the value of x required for the emission of blue light of wavelength 400nm is (take hc ≈ 1200 eV - nm)a)0.95b)0.75c)0.50d)0.33Correct answer is option 'B'. Can you explain this answer?.
Solutions for The active medium in a blue LED (light emitting diode) is a GaxIn1-xN alloy. The band gaps of GaN and InN are 3.5eV and 1.5eV respectively. If the band gap of GaxIn1-xN varies approximately linearly with x , the value of x required for the emission of blue light of wavelength 400nm is (take hc ≈ 1200 eV - nm)a)0.95b)0.75c)0.50d)0.33Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for UGC NET.
Download more important topics, notes, lectures and mock test series for UGC NET Exam by signing up for free.
Here you can find the meaning of The active medium in a blue LED (light emitting diode) is a GaxIn1-xN alloy. The band gaps of GaN and InN are 3.5eV and 1.5eV respectively. If the band gap of GaxIn1-xN varies approximately linearly with x , the value of x required for the emission of blue light of wavelength 400nm is (take hc ≈ 1200 eV - nm)a)0.95b)0.75c)0.50d)0.33Correct answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
The active medium in a blue LED (light emitting diode) is a GaxIn1-xN alloy. The band gaps of GaN and InN are 3.5eV and 1.5eV respectively. If the band gap of GaxIn1-xN varies approximately linearly with x , the value of x required for the emission of blue light of wavelength 400nm is (take hc ≈ 1200 eV - nm)a)0.95b)0.75c)0.50d)0.33Correct answer is option 'B'. Can you explain this answer?, a detailed solution for The active medium in a blue LED (light emitting diode) is a GaxIn1-xN alloy. The band gaps of GaN and InN are 3.5eV and 1.5eV respectively. If the band gap of GaxIn1-xN varies approximately linearly with x , the value of x required for the emission of blue light of wavelength 400nm is (take hc ≈ 1200 eV - nm)a)0.95b)0.75c)0.50d)0.33Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of The active medium in a blue LED (light emitting diode) is a GaxIn1-xN alloy. The band gaps of GaN and InN are 3.5eV and 1.5eV respectively. If the band gap of GaxIn1-xN varies approximately linearly with x , the value of x required for the emission of blue light of wavelength 400nm is (take hc ≈ 1200 eV - nm)a)0.95b)0.75c)0.50d)0.33Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice The active medium in a blue LED (light emitting diode) is a GaxIn1-xN alloy. The band gaps of GaN and InN are 3.5eV and 1.5eV respectively. If the band gap of GaxIn1-xN varies approximately linearly with x , the value of x required for the emission of blue light of wavelength 400nm is (take hc ≈ 1200 eV - nm)a)0.95b)0.75c)0.50d)0.33Correct answer is option 'B'. Can you explain this answer? tests, examples and also practice UGC NET tests.
|
|
Explore Courses for UGC NET exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup