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A wooden block of dimensions 6m*6m*1m (height) and specific gravity 0.5 floats in water with 600kg mass on it .the volume of the submerged tmslab in m^3 is : A) 3.6 B) 14.4 C)15 D) 18.6?
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A wooden block of dimensions 6m*6m*1m (height) and specific gravity 0....
Given:
Dimensions of the wooden block: 6m x 6m x 1m
Specific gravity of the wooden block: 0.5
Mass on the wooden block: 600kg
To find:
The volume of the submerged portion of the wooden block
Solution:
Step 1: Calculate the weight of the wooden block:
The weight of the wooden block can be calculated using the formula:
Weight = mass x acceleration due to gravity
Given:
Mass = 600kg
Acceleration due to gravity = 9.8 m/s^2
Weight of the wooden block = 600kg x 9.8 m/s^2 = 5880 N
Step 2: Calculate the weight of the water displaced:
The weight of the water displaced is equal to the weight of the wooden block.
Weight of the water displaced = 5880 N
Step 3: Calculate the volume of the water displaced:
The volume of the water displaced can be calculated using the formula:
Volume = Weight of water displaced / Density of water
Given:
Density of water = 1000 kg/m^3 (approximately)
Volume of water displaced = 5880 N / 1000 kg/m^3 = 5.88 m^3
Step 4: Calculate the volume of the submerged portion of the wooden block:
The volume of the submerged portion of the wooden block is equal to the volume of water displaced.
Volume of submerged portion = 5.88 m^3
Therefore, the volume of the submerged portion of the wooden block is 5.88 m^3.
Answer:
The volume of the submerged portion of the wooden block is 5.88 m^3.
Dimensions of the wooden block: 6m x 6m x 1m
Specific gravity of the wooden block: 0.5
Mass on the wooden block: 600kg
To find:
The volume of the submerged portion of the wooden block
Solution:
Step 1: Calculate the weight of the wooden block:
The weight of the wooden block can be calculated using the formula:
Weight = mass x acceleration due to gravity
Given:
Mass = 600kg
Acceleration due to gravity = 9.8 m/s^2
Weight of the wooden block = 600kg x 9.8 m/s^2 = 5880 N
Step 2: Calculate the weight of the water displaced:
The weight of the water displaced is equal to the weight of the wooden block.
Weight of the water displaced = 5880 N
Step 3: Calculate the volume of the water displaced:
The volume of the water displaced can be calculated using the formula:
Volume = Weight of water displaced / Density of water
Given:
Density of water = 1000 kg/m^3 (approximately)
Volume of water displaced = 5880 N / 1000 kg/m^3 = 5.88 m^3
Step 4: Calculate the volume of the submerged portion of the wooden block:
The volume of the submerged portion of the wooden block is equal to the volume of water displaced.
Volume of submerged portion = 5.88 m^3
Therefore, the volume of the submerged portion of the wooden block is 5.88 m^3.
Answer:
The volume of the submerged portion of the wooden block is 5.88 m^3.
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A wooden block of dimensions 6m*6m*1m (height) and specific gravity 0.5 floats in water with 600kg mass on it .the volume of the submerged tmslab in m^3 is : A) 3.6 B) 14.4 C)15 D) 18.6?
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A wooden block of dimensions 6m*6m*1m (height) and specific gravity 0.5 floats in water with 600kg mass on it .the volume of the submerged tmslab in m^3 is : A) 3.6 B) 14.4 C)15 D) 18.6? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A wooden block of dimensions 6m*6m*1m (height) and specific gravity 0.5 floats in water with 600kg mass on it .the volume of the submerged tmslab in m^3 is : A) 3.6 B) 14.4 C)15 D) 18.6? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A wooden block of dimensions 6m*6m*1m (height) and specific gravity 0.5 floats in water with 600kg mass on it .the volume of the submerged tmslab in m^3 is : A) 3.6 B) 14.4 C)15 D) 18.6?.
A wooden block of dimensions 6m*6m*1m (height) and specific gravity 0.5 floats in water with 600kg mass on it .the volume of the submerged tmslab in m^3 is : A) 3.6 B) 14.4 C)15 D) 18.6? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A wooden block of dimensions 6m*6m*1m (height) and specific gravity 0.5 floats in water with 600kg mass on it .the volume of the submerged tmslab in m^3 is : A) 3.6 B) 14.4 C)15 D) 18.6? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A wooden block of dimensions 6m*6m*1m (height) and specific gravity 0.5 floats in water with 600kg mass on it .the volume of the submerged tmslab in m^3 is : A) 3.6 B) 14.4 C)15 D) 18.6?.
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