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In a uniformly accelerated motion, the speed varies from 0 to 20 m/s in 4 s. What is the average speed during the motion?
  • a)
    10 m/s
  • b)
    20 m/s
  • c)
    0 m/s
  • d)
    15 m/s
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
In a uniformly accelerated motion, the speed varies from 0 to 20 m/s i...
From first equation of motion we have, v = u + at, which implies that a = 5 m/s2. From second equation of motion we have s = ut + (1/2)at2, which implies that s = 40 m. Average speed = s/t = 40/4 = 10 m/s.
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Most Upvoted Answer
In a uniformly accelerated motion, the speed varies from 0 to 20 m/s i...
Given data:
Initial speed, u = 0 m/s
Final speed, v = 20 m/s
Time, t = 4 s

Calculating Average Speed:
Average speed is given by the formula:
Average speed = Total distance / Total time

Calculating Total Distance:
Using the formula for uniformly accelerated motion:
v = u + at
where,
v = final speed = 20 m/s
u = initial speed = 0 m/s
a = acceleration
t = time = 4 s
Substitute the values and solve for acceleration:
20 = 0 + 4a
a = 20 / 4
a = 5 m/s^2
Now, using the formula:
v^2 = u^2 + 2as
where,
v = final speed = 20 m/s
u = initial speed = 0 m/s
a = acceleration = 5 m/s^2
s = total distance
Substitute the values and solve for total distance:
20^2 = 0 + 2 * 5 * s
400 = 10s
s = 400 / 10
s = 40 m

Calculating Average Speed:
Average speed = Total distance / Total time
Average speed = 40 m / 4 s
Average speed = 10 m/s
Therefore, the average speed during the motion is 10 m/s, which corresponds to option 'a'.
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In a uniformly accelerated motion, the speed varies from 0 to 20 m/s in 4 s. What is the average speed during the motion?a)10 m/sb)20 m/sc)0 m/sd)15 m/sCorrect answer is option 'A'. Can you explain this answer?
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