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How to check aromaticity in fused ring if one ring is aromatic while other is not .is the whole compound be aromatic or not?please reply fast?
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How to check aromaticity in fused ring if one ring is aromatic while o...
**Checking Aromaticity in Fused Rings with One Aromatic and One Non-Aromatic Ring**

To determine whether a compound with fused rings is aromatic or not when one ring is aromatic and the other is not, we need to follow a set of rules known as the Huckel's rule. These rules help in determining the aromaticity of a compound based on its molecular structure and the number of π electrons.

**Huckel's Rule**
According to Huckel's rule, a compound is considered aromatic if it meets the following criteria:

1. The compound must be cyclic, meaning it forms a closed loop.
2. The compound must be planar, with all atoms lying in the same plane.
3. The compound must be fully conjugated, meaning all the atoms in the ring must be sp2 hybridized and have unhybridized p orbitals.
4. The compound must have 4n+2 π electrons, where n is an integer.

**Determining Aromaticity in Fused Rings**

When dealing with fused rings, we can evaluate the aromaticity of the compound by analyzing each ring individually and then considering their interaction.

1. **Analyze the Aromatic Ring**: Determine if the aromatic ring meets Huckel's rule. If it is cyclic, planar, and has 4n+2 π electrons, then it is considered aromatic.

2. **Analyze the Non-Aromatic Ring**: Determine if the non-aromatic ring meets Huckel's rule. If it does not have 4n+2 π electrons, it is considered non-aromatic.

3. **Consider the Interaction**: If the aromatic and non-aromatic rings are fused together, their interaction can affect the overall aromaticity of the compound. The interaction between the rings can lead to delocalization of the π electrons, resulting in a loss or gain of aromaticity.

4. **Evaluate the Overall Compound**: If the interaction between the rings disrupts the aromaticity of the compound, it may no longer be considered aromatic. The overall compound's aromaticity will depend on the extent of the interaction and the number of π electrons present in the fused system.

Therefore, the entire compound will only be aromatic if both rings individually meet Huckel's rule and the interaction between them does not disrupt the aromaticity. If the interaction results in the loss of aromaticity in either or both rings, the compound as a whole may not be aromatic.
Community Answer
How to check aromaticity in fused ring if one ring is aromatic while o...
(4n+2)electrons..no i think its not an aromatic if it is fused with non aromatic..bcz aromatic compound should hv cyclic /planar/it must satisfy huckel's rule ...non aromatic must violate any of these conditions...Iam not sure about the ans but i think it doesnot give aromatic...
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Can you explain the answer of this question below:On the basis of aromaticity, there are three types of compounds i.e. aromatic, non-aromatic and antiaromatic.The increasing order of stability of these compounds are is under:Anti-aromatic compound non-aromatic compound aromatic compounds. Compounds to be aromaticfollow the following conditions (according to valence bond theory)(i) The compounds must be be cyclic in structure having (4n + 2) e, where n = Hckels number = 0, 1,2, 3 et.c(ii) The each atoms of the cyclic structure must have unhybridised p-orbital i.e. the atoms of thecompounds have unhybridised p-orbital i.e. usually have sp2 hybrid or planar.(iii) There must be a ring current of electrons in the ring or cyclic structure i.e. cyclic structure mustundergo resonance .Compounds to be anti-aromatic, it must have 4ne where n = 1, 2 and it must be planar and undergoresonance. Non-aromatic compounds the name itself spells that compounds must be non-planarirrespective of number of electrons. Either it has 4ne or (4n + 2) electrons it does not matter.The rate of reaction of any aromatic compounds depends upon the following factors:(i) Electron density(ii) stability of carbocation producedHigher the amount of electron density of the ring, higher will be its rate towards aromatic electrophilicsubstitution and vice-versa. Similarly, higher will be the stability of the produced carbocation after theattack of electrophile, higher will be its rate towards aromatic electrophilic substitution. There is a greateffect of kinetic labelling on the rate of aromatic electrophilic substitution. As we known that higher theatomic weight or, molecualr weight, higher will be the van der Waals force of attraction or, bond energy.Since there will be effect of kienetic labelling if the 2nd step of the reaction will be the slow step, (r.d.s.)otherwise there will be no effect of kinetic labelling.Q. Which of the following is correct order of the rate of reaction of C6H6, C6D6 and C6T6 towardsnitrations?A:C6H6 C6D6 C6T6B:C6H6 = C6D6 = C6T6C:C6H6 C6D6 = C6T6D:C6T6 C6D6 C6H6The answer is b.

On the basis of aromaticity, there are three types of compounds i.e. aromatic, non-aromatic and antiaromatic. The increasing order of stability of these compounds are is under: Anti-aromatic compound < non-aromatic compound < aromatic compounds. Compounds to be aromaticfollow the following conditions (according to valence bond theory)(i) The compounds must be be cyclic in structure having (4n + 2)π e–, where n = Hückel’s number = 0, 1, 2, 3 et.c(ii) The each atoms of the cyclic structure must have unhybridised p-orbital i.e. the atoms of the compounds have unhybridised p-orbital i.e. usually have sp2 hybrid or planar.(iii) There must be a ring current of π electrons in the ring or cyclic structure i.e. cyclic structure mustundergo resonance .Compounds to be anti-aromatic, it must have 4nπe– where n = 1, 2… and it must be planar and undergo resonance. Non-aromatic compounds the name itself spells that compounds must be non-planarirrespective of number of π electrons. Either it has 4nπe– or (4n + 2) π electrons it does not matter.The rate of reaction of any aromatic compounds depends upon the following factors:(i) Electron density(ii) stability of carbocation producedHigher the amount of electron density of the ring, higher will be its rate towards aromatic electrophilic substitution and vice-versa. Similarly, higher will be the stability of the produced carbocation after the attack of electrophile, higher will be its rate towards aromatic electrophilic substitution. There is a great effect of kinetic labelling on the rate of aromatic electrophilic substitution. As we known that higher the atomic weight or, molecualr weight, higher will be the van der Waal’s force of attraction or, bond energy. Since there will be effect of kienetic labelling if the 2nd step of the reaction will be the slow step, (r.d.s.) otherwise there will be no effect of kinetic labelling.Q. Which of the following is correct order of the rate of reaction of C6H6, C6D6 and C6T6 towardssulphonation?

How to check aromaticity in fused ring if one ring is aromatic while other is not .is the whole compound be aromatic or not?please reply fast?
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