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+9e and +e C charges are placed at a distance of 16 cm and a charge q is placed b/w them in such a way that the charge q is in equilibrium calculate the distance of charge q from 9e charge?
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+9e and +e C charges are placed at a distance of 16 cm and a charge q ...
Two charge +9e and +1e are kept at a distance of 16cm from each other Let a q charge is kept r distance from +9e in such a way that it remains in equilibrium......Now, at equilibrium .....Force act on q due to +9e = Force act on q due to +1e ......K(+9e)q/r² = k(+1e)q/(16 - r)² .....9/r² = 1/(16 - r)² .......Taking square root both sides, .....3/r = 1/(16 - r) .....48 - 3r = r .....48 = 4r .....r = 12cm ......Hence, a point charge q is kept 12cm from +9e
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+9e and +e C charges are placed at a distance of 16 cm and a charge q is placed b/w them in such a way that the charge q is in equilibrium calculate the distance of charge q from 9e charge?
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+9e and +e C charges are placed at a distance of 16 cm and a charge q is placed b/w them in such a way that the charge q is in equilibrium calculate the distance of charge q from 9e charge? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about +9e and +e C charges are placed at a distance of 16 cm and a charge q is placed b/w them in such a way that the charge q is in equilibrium calculate the distance of charge q from 9e charge? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for +9e and +e C charges are placed at a distance of 16 cm and a charge q is placed b/w them in such a way that the charge q is in equilibrium calculate the distance of charge q from 9e charge?.
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