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A rectangular open channel having bed width 2 m is laid at a bed slope - 0.0009 and carries a flow of 10 cumec. What is its normal depth of flow?
- a)It needs a calculator for doing the calculations and hence one cannot answer it now
- b)Many data are missing in the problem statement
- c)The problem statement is wrong
- d)The uniform flow does not exist for the channel
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
A rectangular open channel having bed width 2 m is laid at a bed slope...
As per Manning's equation, the discharge in an open channel is given by
Where A = Area of Flow, R = Hydraulic radius, S = Bed Slope of the channel,
When the slope (S) < 0, So the slope is adverse slope
So, uniform discharge or depth cannot be established when the slope is negative
Classification of the channel:
Where A = Area of Flow, R = Hydraulic radius, S = Bed Slope of the channel,
When the slope (S) < 0, So the slope is adverse slope
So, uniform discharge or depth cannot be established when the slope is negative
Classification of the channel:
Most Upvoted Answer
A rectangular open channel having bed width 2 m is laid at a bed slope...
Problem Analysis:
The problem states that a rectangular open channel with a bed width of 2 m is laid at a bed slope of -0.0009 and carries a flow of 10 cumec. We are asked to determine the normal depth of flow for this channel.
Uniform Flow:
Uniform flow occurs when the flow velocity, depth, and cross-sectional area remain constant along the length of the channel. In this case, we are assuming that the flow in the channel is uniform.
Manning's Equation:
To determine the normal depth of flow, we can use Manning's equation, which relates the flow velocity, channel slope, cross-sectional area, and hydraulic radius.
Manning's equation is given as:
Q = (1/n) * A * R^(2/3) * S^(1/2)
Where:
Q = Flow rate (m^3/s)
A = Cross-sectional area of flow (m^2)
R = Hydraulic radius (m)
S = Channel slope (m/m)
n = Manning's roughness coefficient
Calculation:
In this problem, we are given the flow rate (Q = 10 cumec = 10 m^3/s), bed width (B = 2 m), and channel slope (S = -0.0009). However, we are not given the Manning's roughness coefficient (n).
Since the problem states that the flow is uniform, we can assume that the channel has a trapezoidal or rectangular cross-section.
Trapezoidal Cross-section:
If the channel has a trapezoidal cross-section, we would need additional information such as the side slope, bottom width, and side slope angle to calculate the normal depth.
Rectangular Cross-section:
If the channel has a rectangular cross-section, we can use the following equations to calculate the cross-sectional area (A) and hydraulic radius (R):
A = B * y
R = A / (B + 2y)
Where:
B = Bed width (m)
y = Depth of flow (m)
Since we are not given the side slope or bottom width, we cannot determine the normal depth for a trapezoidal cross-section. Therefore, option 'B' is incorrect.
Conclusion:
Based on the given information, we cannot determine the normal depth of flow for the channel. Therefore, option 'D' is the correct answer.
The problem states that a rectangular open channel with a bed width of 2 m is laid at a bed slope of -0.0009 and carries a flow of 10 cumec. We are asked to determine the normal depth of flow for this channel.
Uniform Flow:
Uniform flow occurs when the flow velocity, depth, and cross-sectional area remain constant along the length of the channel. In this case, we are assuming that the flow in the channel is uniform.
Manning's Equation:
To determine the normal depth of flow, we can use Manning's equation, which relates the flow velocity, channel slope, cross-sectional area, and hydraulic radius.
Manning's equation is given as:
Q = (1/n) * A * R^(2/3) * S^(1/2)
Where:
Q = Flow rate (m^3/s)
A = Cross-sectional area of flow (m^2)
R = Hydraulic radius (m)
S = Channel slope (m/m)
n = Manning's roughness coefficient
Calculation:
In this problem, we are given the flow rate (Q = 10 cumec = 10 m^3/s), bed width (B = 2 m), and channel slope (S = -0.0009). However, we are not given the Manning's roughness coefficient (n).
Since the problem states that the flow is uniform, we can assume that the channel has a trapezoidal or rectangular cross-section.
Trapezoidal Cross-section:
If the channel has a trapezoidal cross-section, we would need additional information such as the side slope, bottom width, and side slope angle to calculate the normal depth.
Rectangular Cross-section:
If the channel has a rectangular cross-section, we can use the following equations to calculate the cross-sectional area (A) and hydraulic radius (R):
A = B * y
R = A / (B + 2y)
Where:
B = Bed width (m)
y = Depth of flow (m)
Since we are not given the side slope or bottom width, we cannot determine the normal depth for a trapezoidal cross-section. Therefore, option 'B' is incorrect.
Conclusion:
Based on the given information, we cannot determine the normal depth of flow for the channel. Therefore, option 'D' is the correct answer.
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A rectangular open channel having bed width 2 m is laid at a bed slope - 0.0009 and carries a flow of 10 cumec. What is its normal depth of flow?a)It needs a calculator for doing the calculations and hence one cannot answer it nowb)Many data are missing in the problem statementc)The problem statement is wrongd)The uniform flow does not exist for the channelCorrect answer is option 'D'. Can you explain this answer?
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A rectangular open channel having bed width 2 m is laid at a bed slope - 0.0009 and carries a flow of 10 cumec. What is its normal depth of flow?a)It needs a calculator for doing the calculations and hence one cannot answer it nowb)Many data are missing in the problem statementc)The problem statement is wrongd)The uniform flow does not exist for the channelCorrect answer is option 'D'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A rectangular open channel having bed width 2 m is laid at a bed slope - 0.0009 and carries a flow of 10 cumec. What is its normal depth of flow?a)It needs a calculator for doing the calculations and hence one cannot answer it nowb)Many data are missing in the problem statementc)The problem statement is wrongd)The uniform flow does not exist for the channelCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A rectangular open channel having bed width 2 m is laid at a bed slope - 0.0009 and carries a flow of 10 cumec. What is its normal depth of flow?a)It needs a calculator for doing the calculations and hence one cannot answer it nowb)Many data are missing in the problem statementc)The problem statement is wrongd)The uniform flow does not exist for the channelCorrect answer is option 'D'. Can you explain this answer?.
A rectangular open channel having bed width 2 m is laid at a bed slope - 0.0009 and carries a flow of 10 cumec. What is its normal depth of flow?a)It needs a calculator for doing the calculations and hence one cannot answer it nowb)Many data are missing in the problem statementc)The problem statement is wrongd)The uniform flow does not exist for the channelCorrect answer is option 'D'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A rectangular open channel having bed width 2 m is laid at a bed slope - 0.0009 and carries a flow of 10 cumec. What is its normal depth of flow?a)It needs a calculator for doing the calculations and hence one cannot answer it nowb)Many data are missing in the problem statementc)The problem statement is wrongd)The uniform flow does not exist for the channelCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A rectangular open channel having bed width 2 m is laid at a bed slope - 0.0009 and carries a flow of 10 cumec. What is its normal depth of flow?a)It needs a calculator for doing the calculations and hence one cannot answer it nowb)Many data are missing in the problem statementc)The problem statement is wrongd)The uniform flow does not exist for the channelCorrect answer is option 'D'. Can you explain this answer?.
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