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The depth of flow in an irrigation channel is 2 m and the value of critical velocity ratio is 1.1. What is the critical velocity (m/sec) of the channel using Kennedy's theory?
  • a)
    2 × (0.55)0.64
  • b)
    0.605 × (2)0.16
  • c)
    1.10 × (1.55)0.64
  • d)
    0.605 × (2)0.64
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
The depth of flow in an irrigation channel is 2 m and the value of cri...
Kennedy’s theory:
  • According to Kennedy, the critical velocity (vo) in a channel is defined as the mean velocity which will keep the channel free from silting and scouring.
  • Silting occurs when the velocity of flow in the canal is less than the critical velocity and particles get sufficient time to settle down hence silting occurs.
  • But when the velocity of flow is greater than critical flow, particles do not get enough time to settle down, but due to their high kinetic energy, it scours the bed of the channel, and hence scouring occurs.
  • From the discussion above it is clear that critical velocity is neither minimum (silting velocity) nor maximum (scouring) velocity, so its magnitude will be somewhat between these two velocity
  • The critical velocity (vo) is given as V0 = 0.55 m d0⋅64
Where,
m = critical velocity ratio and d = depth of water in the channel (in meters) = 2 m
So, Vo = 0.55 × 1.1 × 20.64
Vo = 0.605 × 20.64
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Most Upvoted Answer
The depth of flow in an irrigation channel is 2 m and the value of cri...
Understanding Critical Velocity in Irrigation Channels
To determine the critical velocity using Kennedy's theory, we need to apply the formula that relates depth and critical velocity. The critical velocity ratio is given as 1.1, and the depth of flow is 2 m.
Critical Velocity Formula
Kennedy's theory provides the formula for critical velocity (V_c) as follows:
V_c = K * (D)^n
Where:
- K is a constant that depends on the critical velocity ratio,
- D is the depth of flow,
- n is an exponent that varies depending on the specific flow characteristics.
In this case, the critical velocity ratio is 1.1, indicating that K can be expressed in terms of this ratio.
Applying the Values
Given:
- Depth (D) = 2 m
- Critical Velocity Ratio = 1.1
Using Kennedy's theory with the provided options, we focus on option D:
Option D: Calculation
Option D provides:
0.605 × (2)^0.64
Now, we calculate:
- 2 raised to the power of 0.64 yields a specific value.
- Multiply that value by 0.605 to get the critical velocity.
Why Option D is Correct
The choice of constants and exponent in option D aligns with the formula used in Kennedy's theory. It reflects the relationship between critical velocity, depth, and the critical velocity ratio accurately.
In conclusion, option D is the correct answer because it appropriately utilizes the formula and parameters provided by Kennedy's theory for calculating critical velocity in an irrigation channel.
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The depth of flow in an irrigation channel is 2 m and the value of critical velocity ratio is 1.1. What is the critical velocity (m/sec) of the channel using Kennedys theory?a)2 × (0.55)0.64b)0.605 × (2)0.16c)1.10 × (1.55)0.64d)0.605 × (2)0.64Correct answer is option 'D'. Can you explain this answer? for Civil Engineering (CE) 2025 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about The depth of flow in an irrigation channel is 2 m and the value of critical velocity ratio is 1.1. What is the critical velocity (m/sec) of the channel using Kennedys theory?a)2 × (0.55)0.64b)0.605 × (2)0.16c)1.10 × (1.55)0.64d)0.605 × (2)0.64Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The depth of flow in an irrigation channel is 2 m and the value of critical velocity ratio is 1.1. What is the critical velocity (m/sec) of the channel using Kennedys theory?a)2 × (0.55)0.64b)0.605 × (2)0.16c)1.10 × (1.55)0.64d)0.605 × (2)0.64Correct answer is option 'D'. Can you explain this answer?.
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