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A frictionless uniform ring of mass m has 2 beads A and B of mass m each ;both being able to slide on the ring.initially the ring lies on a frictionless horizontal table and both beads are given velocities v towards +x axis.the relative velocity of the beads wrt to each other just before they collide is?
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A frictionless uniform ring of mass m has 2 beads A and B of mass m ea...
Problem

A frictionless uniform ring of mass m has 2 beads A and B of mass m each; both being able to slide on the ring. Initially, the ring lies on a frictionless horizontal table, and both beads are given velocities v towards the x-axis. The relative velocity of the beads wrt to each other just before they collide is? Explain in detail.


Solution

Let's assume that the ring has a radius R.


Step 1: Find the velocity of the center of mass of the system

The velocity of the center of mass of the system can be found by applying the conservation of momentum.


Initial momentum = Final momentum

2mv = (m + 2m)VCM

VCM = v/3


Step 2: Find the velocity of the beads wrt to the center of mass

Let the velocities of bead A and B wrt to the center of mass be vA and vB respectively.


Using the relative velocity formula, we get:

vrel = vB - vA


Step 3: Find the velocities of the beads

As the ring is a uniform circular motion, the velocity of the beads can be found by using the formula:


v = ωR


where ω is the angular velocity of the ring.


Initial velocity of bead A = v

Velocity of bead A after time t = vA = v - ωt


Initial velocity of bead B = v

Velocity of bead B after time t = vB = v + ωt


Step 4: Find the time taken for the beads to collide

The beads will collide when they meet each other on the ring. Let the time taken for the beads to collide be tc.


Distance traveled by bead A = Distance traveled by bead B

∴ (v - ωtc)tc = (v + ωtc)tc

∴ tc = R/ω


Step 5: Find the relative velocity of the beads just before they collide

Substituting tc in the expression for vrel, we get:


vrel = vB - vA

= (v + ωtc) - (v - ωtc)

= 2ωtc


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A frictionless uniform ring of mass m has 2 beads A and B of mass m each ;both being able to slide on the ring.initially the ring lies on a frictionless horizontal table and both beads are given velocities v towards +x axis.the relative velocity of the beads wrt to each other just before they collide is?
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A frictionless uniform ring of mass m has 2 beads A and B of mass m each ;both being able to slide on the ring.initially the ring lies on a frictionless horizontal table and both beads are given velocities v towards +x axis.the relative velocity of the beads wrt to each other just before they collide is? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A frictionless uniform ring of mass m has 2 beads A and B of mass m each ;both being able to slide on the ring.initially the ring lies on a frictionless horizontal table and both beads are given velocities v towards +x axis.the relative velocity of the beads wrt to each other just before they collide is? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A frictionless uniform ring of mass m has 2 beads A and B of mass m each ;both being able to slide on the ring.initially the ring lies on a frictionless horizontal table and both beads are given velocities v towards +x axis.the relative velocity of the beads wrt to each other just before they collide is?.
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