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What will be printed after execution of the following code? void main() { int arr[5] = {5,6,7,8,9}; printf("%d", arr[6]); }?
Most Upvoted Answer
What will be printed after execution of the following code? void main(...
Output:
Segmentation fault (core dumped)
Explanation:
The given code declares an array 'arr' of size 5 and initializes it with the values 5, 6, 7, 8, and 9. It then tries to print the value at index 6 of the array using the printf() function with the format specifier %d.
However, there are a few issues with the code that lead to a segmentation fault.
1. Array Index Out of Bounds:
The array 'arr' has a size of 5, which means it has indices from 0 to 4. But the code tries to access the value at index 6, which is beyond the bounds of the array. This results in undefined behavior and can cause a segmentation fault.
2. Segmentation Fault:
A segmentation fault occurs when a program tries to access a memory location that it is not allowed to access. In this case, the code tries to access a memory location beyond the bounds of the array, which is not allowed, leading to a segmentation fault.
3. Core Dumped:
When a program encounters a segmentation fault, it is terminated and a core dump is generated. A core dump is a file that contains the memory contents of the program at the time of the crash. It can be analyzed to debug the program and understand the cause of the crash.
In summary, the given code will result in a segmentation fault and the program will terminate with a "Segmentation fault (core dumped)" error message. The main reason for this error is accessing an array element outside its bounds.
Segmentation fault (core dumped)
Explanation:
The given code declares an array 'arr' of size 5 and initializes it with the values 5, 6, 7, 8, and 9. It then tries to print the value at index 6 of the array using the printf() function with the format specifier %d.
However, there are a few issues with the code that lead to a segmentation fault.
1. Array Index Out of Bounds:
The array 'arr' has a size of 5, which means it has indices from 0 to 4. But the code tries to access the value at index 6, which is beyond the bounds of the array. This results in undefined behavior and can cause a segmentation fault.
2. Segmentation Fault:
A segmentation fault occurs when a program tries to access a memory location that it is not allowed to access. In this case, the code tries to access a memory location beyond the bounds of the array, which is not allowed, leading to a segmentation fault.
3. Core Dumped:
When a program encounters a segmentation fault, it is terminated and a core dump is generated. A core dump is a file that contains the memory contents of the program at the time of the crash. It can be analyzed to debug the program and understand the cause of the crash.
In summary, the given code will result in a segmentation fault and the program will terminate with a "Segmentation fault (core dumped)" error message. The main reason for this error is accessing an array element outside its bounds.
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What will be printed after execution of the following code? void main() { int arr[5] = {5,6,7,8,9}; printf("%d", arr[6]); }?
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What will be printed after execution of the following code? void main() { int arr[5] = {5,6,7,8,9}; printf("%d", arr[6]); }? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about What will be printed after execution of the following code? void main() { int arr[5] = {5,6,7,8,9}; printf("%d", arr[6]); }? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What will be printed after execution of the following code? void main() { int arr[5] = {5,6,7,8,9}; printf("%d", arr[6]); }?.
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