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As per IS : 10500-2012, for drinking water, in the absence of alternate source of water, the permissible limit for fluorides is
- a)1.0 mg/L
- b)1.5 mg/L
- c)2.0 mg/L
- d)2.5 mg/L
Correct answer is option 'B'. Can you explain this answer?
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As per IS : 10500-2012, for drinking water, in the absence of alternat...
Water quality for different compounds As per l.S.10500 are as follows:
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As per IS : 10500-2012, for drinking water, in the absence of alternat...
Understanding Fluoride Limits in Drinking Water
In the context of drinking water quality, the permissible limit for fluoride is crucial for public health. According to IS: 10500-2012, the acceptable fluoride concentration is set to ensure safe drinking water.
Permissible Limit of Fluoride
- The permissible limit for fluorides in drinking water, in the absence of alternate sources, is 1.5 mg/L.
- This threshold is established to prevent dental and skeletal fluorosis, which can occur due to excessive fluoride intake.
Reasons for the Limit
- Health Considerations: Fluoride is beneficial for dental health at low levels, but excessive exposure can lead to adverse health effects.
- Regulatory Standards: The Indian Standard (IS: 10500) aligns with global health guidelines, such as those set by the World Health Organization (WHO).
Consequences of High Fluoride Levels
- Dental Fluorosis: Excess fluoride can cause discoloration and mottling of teeth.
- Skeletal Fluorosis: Long-term exposure can result in joint stiffness and pain due to fluoride accumulation in bones.
Conclusion
- Adhering to the limit of 1.5 mg/L for fluorides in drinking water is essential for safeguarding public health while providing the benefits of fluoride for preventing dental caries. Regular monitoring and assessment of fluoride levels in water sources are vital to ensure compliance with these standards.
In the context of drinking water quality, the permissible limit for fluoride is crucial for public health. According to IS: 10500-2012, the acceptable fluoride concentration is set to ensure safe drinking water.
Permissible Limit of Fluoride
- The permissible limit for fluorides in drinking water, in the absence of alternate sources, is 1.5 mg/L.
- This threshold is established to prevent dental and skeletal fluorosis, which can occur due to excessive fluoride intake.
Reasons for the Limit
- Health Considerations: Fluoride is beneficial for dental health at low levels, but excessive exposure can lead to adverse health effects.
- Regulatory Standards: The Indian Standard (IS: 10500) aligns with global health guidelines, such as those set by the World Health Organization (WHO).
Consequences of High Fluoride Levels
- Dental Fluorosis: Excess fluoride can cause discoloration and mottling of teeth.
- Skeletal Fluorosis: Long-term exposure can result in joint stiffness and pain due to fluoride accumulation in bones.
Conclusion
- Adhering to the limit of 1.5 mg/L for fluorides in drinking water is essential for safeguarding public health while providing the benefits of fluoride for preventing dental caries. Regular monitoring and assessment of fluoride levels in water sources are vital to ensure compliance with these standards.
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As per IS : 10500-2012, for drinking water, in the absence of alternate source of water, the permissible limit for fluorides isa)1.0 mg/Lb)1.5 mg/Lc)2.0 mg/Ld)2.5 mg/LCorrect answer is option 'B'. Can you explain this answer?
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As per IS : 10500-2012, for drinking water, in the absence of alternate source of water, the permissible limit for fluorides isa)1.0 mg/Lb)1.5 mg/Lc)2.0 mg/Ld)2.5 mg/LCorrect answer is option 'B'. Can you explain this answer? for Civil Engineering (CE) 2025 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about As per IS : 10500-2012, for drinking water, in the absence of alternate source of water, the permissible limit for fluorides isa)1.0 mg/Lb)1.5 mg/Lc)2.0 mg/Ld)2.5 mg/LCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for As per IS : 10500-2012, for drinking water, in the absence of alternate source of water, the permissible limit for fluorides isa)1.0 mg/Lb)1.5 mg/Lc)2.0 mg/Ld)2.5 mg/LCorrect answer is option 'B'. Can you explain this answer?.
As per IS : 10500-2012, for drinking water, in the absence of alternate source of water, the permissible limit for fluorides isa)1.0 mg/Lb)1.5 mg/Lc)2.0 mg/Ld)2.5 mg/LCorrect answer is option 'B'. Can you explain this answer? for Civil Engineering (CE) 2025 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about As per IS : 10500-2012, for drinking water, in the absence of alternate source of water, the permissible limit for fluorides isa)1.0 mg/Lb)1.5 mg/Lc)2.0 mg/Ld)2.5 mg/LCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for As per IS : 10500-2012, for drinking water, in the absence of alternate source of water, the permissible limit for fluorides isa)1.0 mg/Lb)1.5 mg/Lc)2.0 mg/Ld)2.5 mg/LCorrect answer is option 'B'. Can you explain this answer?.
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As per IS : 10500-2012, for drinking water, in the absence of alternate source of water, the permissible limit for fluorides isa)1.0 mg/Lb)1.5 mg/Lc)2.0 mg/Ld)2.5 mg/LCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for As per IS : 10500-2012, for drinking water, in the absence of alternate source of water, the permissible limit for fluorides isa)1.0 mg/Lb)1.5 mg/Lc)2.0 mg/Ld)2.5 mg/LCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of As per IS : 10500-2012, for drinking water, in the absence of alternate source of water, the permissible limit for fluorides isa)1.0 mg/Lb)1.5 mg/Lc)2.0 mg/Ld)2.5 mg/LCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
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