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If ‘ϕ’ is the angle of blade tip at outlet, then maximum hydraulic efficiency of an impulse turbine is
  • a)
  • b)
  • c)
  • d)
Correct answer is option 'A'. Can you explain this answer?
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If ‘’ is the angle of blade tip at outlet, then maximum hy...
The velocity diagram of a Pelton wheel is given below -

V1, V2 = Velocity of the jet at inlet and outlet.
u1, u2 = Velocity of the vane at inlet and outlet.
Vr1, Vr2 = Relative velocity of jet at inlet and outlet.
Vw1, Vw2 = Whirl velocity i.e. component of velocity parallel to the direction of motion.
Vf1, Vf2 = Flow velocity i.e component of velocity perpendicular to the direction of motion.
α = ∠ between the direction of jet and direction of motion.
θ = ∠ between Vr1 and the direction of motion.
β = ∠ between V2 with the direction of motion.
ϕ = ∠ between Vr2 with the direction of motion.
Hydraulic efficiency is given by - 

Given:
For Pelton wheel 
V1 = Vw1, u1 = u2 = u, Vr1 = Vr2.
If Nozzle is 100 % efficient -

Hydraulic efficiency is:

For ηh to be maximum; 

∴ 2u = 2V1 - 2u
⇒ 4u = 2V1
∴  V1 = 2u
Putting this in eq (1)
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If ‘’ is the angle of blade tip at outlet, then maximum hydraulic efficiency of an impulse turbine isa)b)c)d)Correct answer is option 'A'. Can you explain this answer?
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