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The operator for the square of the angular momentum for an electron in a hydrogenic atom is given below.

A correct form of the angular function for the px orbital is
  • a)
    sin θ e2iϕ
  • b)
    sin θ e
  • c)
    cos θ e
  • d)
    cos θ e2iϕ
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
The operator for the square of the angular momentum for an electron in...
The overall wave function for the angular part of H atom will be as follows:

where, A and B are constant.
For px orbital l=1
1. when l=1, ml=0, then 

as, in Y1,0 there is no ϕ part, it will correspond to the pz orbital.
2. when l=1, ml=+1, then 
  • Now, we can calculate the angular wavefunction for pand py orbital by taking linera combination of equation (2) and (3) as follows-
  • Among the given four wavefunction, all the wavefunctions contain a imaginary part which can not be compare with equation (4) to find out the angular function for the px orbital.
  • Comparing the wavefunction sin θ e2iϕ with equation (1), we got ml=2.
  • Which is not possible for p orbital. (the possible value of ml for p orbiatl is -1, 0 and +1).
  • Thus, sin θ e2iϕ is not the correct form of the angular function for the px orbital.
  • Comapring the wavefunctions cos θ eiϕ and cos θ e2iϕ, with equation (2), we found that there is no presence of sinθs.
  • Thus, cos θ eiϕ and cos θ e2iϕ are not the correct form of the angular function for the px orbital.
  • Comparing the wavefunction sin θ e with equation (2), we found that it can be a correct form of the angular function for the px orbital for l=1 and ml=+1.
Hence, the correct form of the angular function for the px orbital is  sin θ e 
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The operator for the square of the angular momentum for an electron in a hydrogenic atom is given below.A correct form of the angular function for the pxorbital isa)sin θ e2ib)sin θ eic)cos θ eid)cos θ e2iCorrect answer is option 'B'. Can you explain this answer?
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