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If two is subtracted from each odd digit and three is added to each even digit in the number 3675249. How many digits will appear twice in the new number thus formed?
  • a)
    1
  • b)
    2
  • c)
    3
  • d)
    4
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
If two is subtracted from each odd digit and three is added to each ev...
Understanding the Problem
To solve the problem, we need to transform each digit of the number 3675249 based on whether it is odd or even.
Transformation Rules
- Odd Digits: Subtract 2
- Even Digits: Add 3
Applying the Transformation
Let's break down the number 3675249 digit by digit:
- 3 (odd): 3 - 2 = 1
- 6 (even): 6 + 3 = 9
- 7 (odd): 7 - 2 = 5
- 5 (odd): 5 - 2 = 3
- 2 (even): 2 + 3 = 5
- 4 (even): 4 + 3 = 7
- 9 (odd): 9 - 2 = 7
Now we compile the new digits:
- Original: 3, 6, 7, 5, 2, 4, 9
- Transformed: 1, 9, 5, 3, 5, 7, 7
Counting the Digits
Now let's look at the transformed digits:
- 1
- 9
- 5 (appears twice)
- 3
- 7 (appears twice)
Identifying Digits that Appear Twice
From the transformed digits, we can see that:
- 5 appears twice
- 7 appears twice
Thus, we have two digits that appear twice.
Conclusion
The total number of digits that appear twice in the new number is 2.
Therefore, the correct answer is option 'B'.
Free Test
Community Answer
If two is subtracted from each odd digit and three is added to each ev...
Subtract 2 from odd digits in given number and add 3 in even digits.
So, in new number there are two digits of five and two digits of seven.
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If two is subtracted from each odd digit and three is added to each even digit in the number 3675249. How many digits will appear twice in the new number thus formed?a)1b)2c)3d)4Correct answer is option 'B'. Can you explain this answer?
Question Description
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