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Two cylindrical bars having same material properties, are carrying tensile load 'P' at its two ends. If the ratio of their length is 2 and ratio of their area of cross-section is 4, what will be the ratio of total extension in the bar?
  • a)
    2
  • b)
    1/2
  • c)
    4
  • d)
    1/4
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
Two cylindrical bars having same material properties, are carrying ten...
δl1 = Pl1/A1E
δl2 = Pl2/A2E
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Two cylindrical bars having same material properties, are carrying tensile load P at its two ends. If the ratio of their length is 2 and ratio of their area of cross-section is 4, what will be the ratio of total extension in the bar?a)2b)1/2c)4d)1/4Correct answer is option 'B'. Can you explain this answer?
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Two cylindrical bars having same material properties, are carrying tensile load P at its two ends. If the ratio of their length is 2 and ratio of their area of cross-section is 4, what will be the ratio of total extension in the bar?a)2b)1/2c)4d)1/4Correct answer is option 'B'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about Two cylindrical bars having same material properties, are carrying tensile load P at its two ends. If the ratio of their length is 2 and ratio of their area of cross-section is 4, what will be the ratio of total extension in the bar?a)2b)1/2c)4d)1/4Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two cylindrical bars having same material properties, are carrying tensile load P at its two ends. If the ratio of their length is 2 and ratio of their area of cross-section is 4, what will be the ratio of total extension in the bar?a)2b)1/2c)4d)1/4Correct answer is option 'B'. Can you explain this answer?.
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