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A liquid which is immiscible in water was steam distilled at 95.2°C at a total pressure of 0.983 atmosphere. What is the mass of the liquid present per gram of water in the distillate?

Molar mass of the liquid is 134.3 gm/mol and vapour pressure of water is 0.84 atm.
(Round off up to 2 decimal places)
Correct answer is '1.27'. Can you explain this answer?
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A liquid which is immiscible in water was steam distilled at 95.2°...
PT = 0.983 atm
Pwater = 0.84 atm
Pliquid = 0.143 atm

Therefore, mass of the liquid present per gram of water in the distillate is 1.27 g.
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A liquid which is immiscible in water was steam distilled at 95.2°...
The steam distillation process involves heating a mixture of two immiscible liquids to vaporize the more volatile component, which is then condensed and collected separately. In this case, the liquid that is immiscible in water was heated and vaporized at a temperature of 95.2 degrees Celsius.

During steam distillation, water is typically used as the solvent and is heated to its boiling point to produce steam. The steam carries the volatile component of the immiscible liquid along with it, while leaving behind the less volatile component. The steam is then condensed back into liquid form, resulting in the separation of the two components.

It is important to note that the boiling point of the immiscible liquid is crucial in determining the appropriate temperature for steam distillation. In this case, the immiscible liquid vaporized at a temperature of 95.2 degrees Celsius, indicating that it has a lower boiling point than water.

By using steam distillation, the immiscible liquid can be effectively separated from water, allowing for the isolation and collection of the volatile component.
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The atmospheric lapse rateFor small volumes of gas, according to kinetic theory of gases, all parts of the gas are at the same temperature. But for huge volumes of gas like atmosphere, assumption of a uniform temperature throughout the gas is not valid. Different parts of the atmosphere are at different temperatures. Apart from the surface of the earth, variations also occur in temperature at different heights in the atmosphere.The decrease in temperature with height called the atmospheric lapse rate is similar at various locations across the surface of the Earth. By analyzing the data collected at various locations, it is found that average global lapse rate is – 6.7 °C/Km.The linear decrease with temperature only occurs in the lower part of the atmosphere called the troposphere. This is the part of the atmosphere in which weather occurs and our planes fly. Above the troposphere is the stratosphere, with an imaginary boundary separating the two layers. In the stratosphere, temperature tends to be relatively constant.Absorption of sunlight at the Earth’s surface warms the troposphere from below, so vertical convection currents are continually mixing in the air. As a parcel of air rises, its pressure drops and it expands. The parcel does work on its surrounding, so that its internal energy and therefore, its temperature drops. Assume that the vertical mixing is so rapid as to be adiabatic and the quantityTP(1 – λ)/λ has a uniform value through the layers of troposphere.(M is molecular mass of the air, R is universal gas constant, g is gravitational acc., P and T are pressure and temperature respectively at the point under consideration and y is height.)Q. Mechanical equilibrium of the atmosphere requires that the pressure decreases with altitude according to . Assuming free fall acceleration to be uniform, then lapse rate is given by

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A liquid which is immiscible in water was steam distilled at 95.2°C at a total pressure of 0.983 atmosphere. What is the mass of the liquid present per gram of water in the distillate?Molar mass of the liquid is 134.3 gm/mol and vapour pressure of water is 0.84 atm.(Round off up to 2 decimal places)Correct answer is '1.27'. Can you explain this answer?
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A liquid which is immiscible in water was steam distilled at 95.2°C at a total pressure of 0.983 atmosphere. What is the mass of the liquid present per gram of water in the distillate?Molar mass of the liquid is 134.3 gm/mol and vapour pressure of water is 0.84 atm.(Round off up to 2 decimal places)Correct answer is '1.27'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A liquid which is immiscible in water was steam distilled at 95.2°C at a total pressure of 0.983 atmosphere. What is the mass of the liquid present per gram of water in the distillate?Molar mass of the liquid is 134.3 gm/mol and vapour pressure of water is 0.84 atm.(Round off up to 2 decimal places)Correct answer is '1.27'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A liquid which is immiscible in water was steam distilled at 95.2°C at a total pressure of 0.983 atmosphere. What is the mass of the liquid present per gram of water in the distillate?Molar mass of the liquid is 134.3 gm/mol and vapour pressure of water is 0.84 atm.(Round off up to 2 decimal places)Correct answer is '1.27'. Can you explain this answer?.
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