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Which of the following will be the correct spin magnetic moment value (B.M.) for the compound Hg[Co(SCN)4]?
(Round off up to 2 decimal places)
Correct answer is '3.87'. Can you explain this answer?
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Which of the following will be the correct spin magnetic moment value ...
The oxidation number of cobalt in the given complex is +2.

Co
+2
 in the complex is sp
3
 hybridised and the complex has a tetrahedral geometry.

Number of unpaired electrons (n) = 3
Spin magnetic moment (ms)
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Which of the following will be the correct spin magnetic moment value ...
Spin Magnetic Moment (B.M.)

The spin magnetic moment is a measure of the magnetic behavior of a compound or an atom. It is represented in units of Bohr magnetons (B.M.) and is calculated based on the number of unpaired electrons in the compound or atom.

Structure of Hg[Co(SCN)4]

To determine the spin magnetic moment of the compound Hg[Co(SCN)4], we first need to understand its structure.

Hg[Co(SCN)4] is a coordination compound where mercury (Hg) acts as a cation and forms coordination bonds with four thiocyanate (SCN) anions. The central cobalt (Co) atom is coordinated to four thiocyanate ligands, forming a tetrahedral geometry.

Determining the Number of Unpaired Electrons

To calculate the spin magnetic moment of Hg[Co(SCN)4], we need to determine the number of unpaired electrons in the compound. This can be done by considering the electronic configuration of the central cobalt atom.

The atomic number of cobalt (Co) is 27. Its electronic configuration is [Ar] 3d^7 4s^2. In a tetrahedral complex, the d orbitals split into two sets of different energy levels - the lower energy set (t2g) and the higher energy set (eg).

Since there are four ligands in the coordination sphere, the d orbitals are split into t2g (dxy, dxz, and dyz) and eg (dx^2-y^2 and dz^2).

Calculating the Number of Unpaired Electrons

To determine the number of unpaired electrons, we need to fill the t2g and eg orbitals with electrons based on Hund's rule. Hund's rule states that electrons occupy separate orbitals with parallel spins before pairing up.

In the case of Hg[Co(SCN)4], the electronic configuration of cobalt is [Ar] 3d^7. Since there are three t2g orbitals, three electrons will occupy these orbitals with parallel spins. Therefore, there will be one unpaired electron in the eg set of orbitals.

Calculating the Spin Magnetic Moment

The spin magnetic moment can be calculated using the formula:

Spin Magnetic Moment (B.M.) = √n(n+2)

Where n is the number of unpaired electrons.

In the case of Hg[Co(SCN)4], there is one unpaired electron (n = 1). Plugging this value into the formula, we get:

Spin Magnetic Moment (B.M.) = √1(1+2) = √3

Rounding off to two decimal places, the spin magnetic moment of Hg[Co(SCN)4] is 3.87 B.M.

Summary

- The spin magnetic moment of a compound or atom is a measure of its magnetic behavior.
- Hg[Co(SCN)4] is a coordination compound with a tetrahedral geometry.
- The electronic configuration of cobalt in Hg[Co(SCN)4] is [Ar] 3d^7.
- Based on the electronic configuration, there is one unpaired electron in the eg set of orbitals.
-
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The orbital and spin angular momentum of the atom influence its magnetic structure and these properties are most directly studied by placing the atom in a magnetic field. Also, a magnetic field can affect the wavelengths of the emitted photons.The angular momentum vector associated with an atomic state can take up only certain specified directions in space. This concept of space quantization was shown by Otto Stern and Walthor Gerlach in their experiment.In the experiment, silver is vapourized in an electric oven and silver atoms spray into the evacuated apparatus through a small hole in the oven wall. The atoms which are electrically neutral but have a magnetic moment, are formed into a narrow beam as they pass through a slit in a screen. The beam, thus collimated, then passes between the poles of an electromagnet and finally, deposits its silver atoms on a glass plate that serves as a detector. The pole faces of the magnet are shaped to make the magnetic field as nonuniform as possible.In a non-uniform magnetic field, there is a net force on a magnetic dipole. Its magnitude and direction depends on the orientation of the dipole. Thus the silver atoms in the beam are deflected up or down, depending on the orientation of their magnetic dipole moments with respect to the z–direction.The potential energy of a magnetic dipole in a magnetic field where is magnetic dipole moment of the atom. From symmetry, the magnetic field at the beam position has no x or y components i.e.The net force Fz on the dipole isThus, the net force depends, not on the magnitude of the field itself, but on its spatial derivative or gradient.The ResultsIf space quantization did not exist, then could take on any value from + to –, the result would be a spreading out of the beam when the magnet was turned ON. However, the beam was split cleanly into two subbeams, each subbeam corresponding to one of the two permitted orientations of the magnetic moment ofthe silver atom, as shown.In a silver atom, all the spin and orbital magnetic moments of the electrons cancel, except for those of the atoms single valance electron. For this electron the orbital magnetic moment is zero because orbital angular momentum is zero (because for electrons of s–orbit, L = 0), leaving only the spin magnetic moment. This can take up only two orientations in a magnetic field, corresponding to ms = +1/2 and ms = – 1/2. Hence there are two subbeams – and not some other number.Q.A hydrogen atom in ground state passes through a magnetic field that has a gradient of 16mT/m in the vertical direction. If vertical component magnetic moment of the atom is 9.3 × 10–24 J/T, then force on it due to the magnetic moment of the electron is

The orbital and spin angular momentum of the atom influence its magnetic structure and these properties are most directly studied by placing the atom in a magnetic field. Also, a magnetic field can affect the wavelengths of the emitted photons.The angular momentum vector associated with an atomic state can take up only certain specified directions in space. This concept of space quantization was shown by Otto Stern and Walthor Gerlach in their experiment.In the experiment, silver is vapourized in an electric oven and silver atoms spray into the evacuated apparatus through a small hole in the oven wall. The atoms which are electrically neutral but have a magnetic moment, are formed into a narrow beam as they pass through a slit in a screen. The beam, thus collimated, then passes between the poles of an electromagnet and finally, deposits its silver atoms on a glass plate that serves as a detector. The pole faces of the magnet are shaped to make the magnetic field as nonuniform as possible.In a non-uniform magnetic field, there is a net force on a magnetic dipole. Its magnitude and direction depends on the orientation of the dipole. Thus the silver atoms in the beam are deflected up or down, depending on the orientation of their magnetic dipole moments with respect to the z–direction.The potential energy of a magnetic dipole in a magnetic field where is magnetic dipole moment of the atom. From symmetry, the magnetic field at the beam position has no x or y components i.e.The net force Fz on the dipole isThus, the net force depends, not on the magnitude of the field itself, but on its spatial derivative or gradient.The ResultsIf space quantization did not exist, then could take on any value from + to –, the result would be a spreading out of the beam when the magnet was turned ON. However, the beam was split cleanly into two subbeams, each subbeam corresponding to one of the two permitted orientations of the magnetic moment ofthe silver atom, as shown.In a silver atom, all the spin and orbital magnetic moments of the electrons cancel, except for those of the atoms single valance electron. For this electron the orbital magnetic moment is zero because orbital angular momentum is zero (because for electrons of s–orbit, L = 0), leaving only the spin magnetic moment. This can take up only two orientations in a magnetic field, corresponding to ms = +1/2 and ms = – 1/2. Hence there are two subbeams – and not some other number.Q.A hydrogen atom in ground state passes through a magnetic field that has a gradient of 16mT/m in the vertical direction. If vertical component magnetic moment of the atom is 9.3 × 10–24 J/T, then force on it due to the magnetic moment of the electron is

The orbital and spin angular momentum of the atom influence its magnetic structure and these properties are most directly studied by placing the atom in a magnetic field. Also, a magnetic field can affect the wavelengths of the emitted photons.The angular momentum vector associated with an atomic state can take up only certain specified directions in space. This concept of space quantization was shown by Otto Stern and Walthor Gerlach in their experiment.In the experiment, silver is vapourized in an electric oven and silver atoms spray into the evacuated apparatus through a small hole in the oven wall. The atoms which are electrically neutral but have a magnetic moment, are formed into a narrow beam as they pass through a slit in a screen. The beam, thus collimated, then passes between the poles of an electromagnet and finally, deposits its silver atoms on a glass plate that serves as a detector. The pole faces of the magnet are shaped to make the magnetic field as nonuniform as possible.In a non-uniform magnetic field, there is a net force on a magnetic dipole. Its magnitude and direction depends on the orientation of the dipole. Thus the silver atoms in the beam are deflected up or down, depending on the orientation of their magnetic dipole moments with respect to the z–direction.The potential energy of a magnetic dipole in a magnetic field where is magnetic dipole moment of the atom. From symmetry, the magnetic field at the beam position has no x or y components i.e.The net force Fz on the dipole isThus, the net force depends, not on the magnitude of the field itself, but on its spatial derivative or gradient.The ResultsIf space quantization did not exist, then could take on any value from + to –, the result would be a spreading out of the beam when the magnet was turned ON. However, the beam was split cleanly into two subbeams, each subbeam corresponding to one of the two permitted orientations of the magnetic moment ofthe silver atom, as shown.In a silver atom, all the spin and orbital magnetic moments of the electrons cancel, except for those of the atoms single valance electron. For this electron the orbital magnetic moment is zero because orbital angular momentum is zero (because for electrons of s–orbit, L = 0), leaving only the spin magnetic moment. This can take up only two orientations in a magnetic field, corresponding to ms = +1/2 and ms = – 1/2. Hence there are two subbeams – and not some other number.Q.A hydrogen atom in ground state passes through a magnetic field that has a gradient of 16mT/m in the vertical direction. If vertical component magnetic moment of the atom is 9.3 × 10–24 J/T, then force on it due to the magnetic moment of the electron is

Which of the following will be the correct spin magnetic moment value (B.M.) for the compound Hg[Co(SCN)4]?(Round off up to 2 decimal places)Correct answer is '3.87'. Can you explain this answer?
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Which of the following will be the correct spin magnetic moment value (B.M.) for the compound Hg[Co(SCN)4]?(Round off up to 2 decimal places)Correct answer is '3.87'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Which of the following will be the correct spin magnetic moment value (B.M.) for the compound Hg[Co(SCN)4]?(Round off up to 2 decimal places)Correct answer is '3.87'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Which of the following will be the correct spin magnetic moment value (B.M.) for the compound Hg[Co(SCN)4]?(Round off up to 2 decimal places)Correct answer is '3.87'. Can you explain this answer?.
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