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Ozonolysis of an organic compound gives formaldehyde as one of the products. This confirms the presence of:
  • a)
    Two ethylenic double bonds
  • b)
    A vinyl group
  • c)
    An isopropyl group
  • d)
    An acetylenic triple bond
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
Ozonolysis of an organic compound gives formaldehyde as one of the pro...
Presence of one vinyl (or ethenyl) group gives formaldehyde as one of the product in ozonolysis.
CH2=CH- on ozonolysis will give HCHO.
  • Ozonolysis is an organic reaction where the unsaturated bonds of alkenes, alkynes, or azo compounds are cleaved with ozone. 
  • Alkenes and alkynes form organic compounds in which the multiple carbon–carbon bond has been replaced by a carbonyl group while azo compounds form nitrosamine.
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Community Answer
Ozonolysis of an organic compound gives formaldehyde as one of the pro...
Presence of a Vinyl Group

Ozonolysis
- Ozonolysis is a chemical reaction in which the carbon-carbon double bonds of an alkene are cleaved to form carbonyl compounds.
- In the case of formaldehyde, it is formed when an alkene containing a vinyl group undergoes ozonolysis.

Definition of a Vinyl Group
- A vinyl group is a functional group in organic chemistry consisting of two carbon atoms connected by a double bond.
- It is commonly represented as -CH=CH2.

Confirmation of Vinyl Group Presence
- The formation of formaldehyde as a product of ozonolysis indicates the presence of a vinyl group in the organic compound.
- This is because the cleavage of the carbon-carbon double bond in the vinyl group leads to the formation of formaldehyde.
Therefore, in the given scenario, the presence of formaldehyde as a product of ozonolysis confirms the existence of a vinyl group in the organic compound.
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Ozonolysis of an organic compound gives formaldehyde as one of the products. This confirms the presence of:a)Two ethylenic double bondsb)A vinyl groupc)An isopropyl groupd)An acetylenic triple bondCorrect answer is option 'B'. Can you explain this answer?
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