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A linear system with H(s) = 1/s is excited by a unit step function input. The output for t > 0 is given by
  • a)
    δ(t)
  • b)
    1
  • c)
    t
  • d)
    t2
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A linear system with H(s) = 1/s is excited by a unit step function inp...
TF = H(s) = 1/s,
Input is unit step, R(s) = 1/s
Now output for t > 0 can be calculated as
C(s) = H(s) x R(s)
C(s) = (1/s) x (1/s)
C(s) = 1 / s2
L-1[C(s)] = t
C(t) = t = ramp function
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Most Upvoted Answer
A linear system with H(s) = 1/s is excited by a unit step function inp...
Given Information:
The transfer function of the linear system is H(s) = 1/s, and it is excited by a unit step function input.

Output for t > 0:
The output for t > 0 can be found by taking the inverse Laplace transform of the product of the input and the transfer function.

Calculation:
- The Laplace transform of a unit step function is 1/s.
- Given transfer function H(s) = 1/s.
- The output Y(s) can be calculated by Y(s) = H(s) * X(s), where X(s) is the Laplace transform of the unit step function.
- Substituting the values, Y(s) = 1/s * 1/s = 1/s^2.
- Taking the inverse Laplace transform of Y(s), we get y(t) = t.

Conclusion:
The correct answer is option 'C', which is t. The output for t > 0 in this linear system excited by a unit step function input is a ramp function with a slope of 1.
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