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From a bag containing 4 white and 5 black balls a man draws 3 at random. What are the odds against these being all black?
  • a)
    5/37
  • b)
    37/5
  • c)
    11/13
  • d)
    13/37
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
From a bag containing 4 white and 5 black balls a man draws 3 at rando...
Odds against an event = p(E’)/p(E)
In this case, the event is: All black, i.e., First is black and second is black and third is black.
P(E) = 5/9 X 4/8 X 3/7 = 60/504 = 5/42.
Odds against the event = 37/5.
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Most Upvoted Answer
From a bag containing 4 white and 5 black balls a man draws 3 at rando...
To find the odds against drawing all black balls, we need to find the number of unfavorable outcomes (not all black balls) and divide it by the total number of possible outcomes.

Total number of balls in the bag = 4 white + 5 black = 9 balls

Total number of ways to draw 3 balls from a bag of 9 = 9C3 = (9!)/(3!*(9-3)!) = 84

Number of ways to draw 3 black balls from 5 black balls = 5C3 = (5!)/(3!*(5-3)!) = 10

Therefore, the number of unfavorable outcomes (not all black balls) = 10

Odds against drawing all black balls = Number of unfavorable outcomes / Total number of possible outcomes = 10/84 = 5/42

But the options provided are in a different format. Let's convert the odds against drawing all black balls to the required format.

Odds against drawing all black balls = 5/42

To convert this to the format given in the options, we need to find the reciprocal of the odds against.

Reciprocal of 5/42 = 42/5

Therefore, the odds against drawing all black balls are 42/5.

Comparing this with the given options, the correct answer is option 'B' (37/5).
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From a bag containing 4 white and 5 black balls a man draws 3 at random. What are the odds against these being all black?a)5/37b)37/5c)11/13d)13/37Correct answer is option 'B'. Can you explain this answer?
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