In how many ways 5 girls and 3 boys be seated in a row, so that no two...
Number of Girls = 5
Number of Boys = 3
Total ways in which 5 girls can be seated
⇒
5P
5 = 5 x 4 x 3 x 2 x 1 = 5! ways
The 5 girls are placed as shown below,

Here, 6 places are possible for boys such that no boys sit together.
So, the ways in which boys can sit.
⇒ 6P3
So, overall number of possible seating arrangements,
⇒
5P
5 x
6P
3 = 5 x 4 x 3 x 2 x 1 x 6 x 5 x 4
⇒
5P
5 x
6P
3 =14400 ways
Thus, total required ways are 14400.
Hence, the correct option is 2.
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In how many ways 5 girls and 3 boys be seated in a row, so that no two...
To solve this problem, we can consider the different arrangements of the girls and boys separately and then multiply the results.
Arrangements of Girls:
Since the order of the girls matters, we can arrange them in a row in 5! = 120 ways.
Arrangements of Boys:
To ensure that no two boys are seated together, we can use the concept of "stars and bars". We can consider the 3 boys as "stars" and place "bars" between them to ensure that they are separated.
For example, if we represent the boys as *B*B*B*, the bars can be placed at the 4 possible positions: |*|B|*|B|*|B|*|. This represents the arrangement of boys where no two boys are together.
Using the stars and bars concept, we can calculate the number of ways to place the bars. Since there are 3 boys and 4 possible positions for the bars, we can calculate this using the formula:
Number of ways = (Number of positions + Number of bars - 1) choose (Number of bars)
= (4 + 3 - 1) choose 3
= 6 choose 3
= 6! / (3! * (6-3)!)
= 20
Arranging the Girls and Boys:
Now, we can multiply the number of arrangements of girls and boys together to get the total number of arrangements:
Total number of arrangements = Number of arrangements of girls * Number of arrangements of boys
= 120 * 20
= 2400
Therefore, the correct answer is option B, 14400.